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Sati [7]
3 years ago
11

− 4 = three fourths(x + 8)

Mathematics
1 answer:
Degger [83]3 years ago
8 0

Start with

-4 = \dfrac{3}{4}(x+8)

Multiply both sides by 4:

-16 = 3(x+8)

Divide both sides by 3:

-\dfrac{16}{3} = x+8

Subtract 8 from both sides:

x = -\dfrac{16}{3}-8 = -\dfrac{16}{3}-\dfrac{24}{3} = -\dfrac{40}{3}

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Answer:

Third answer shown

Step-by-step explanation:

Since each equation has a right side equal to the same thing, y, those right sides must be equal to each other.

                                                    x + 3 = -2x + 6

Add 2x to both sides.                2x          2x

                                                   3x + 3 =  0 + 6

                                                   3x + 3 = 6

Subtract 3 on both sides.                -3     -3

                                                      3x    =    3

Divide both sides by 3.                   x = 1

Now, let's see what y must be if x equals 1.

Line M:  y = x + 3 -->  y = 1 + 3 --> y = 4

Line N: y = -2x +6 --> y = -2(1) +6 --> y = -2 + 6 --> y = 4, confirmed

So the ordered pair (x, y) that satisfies <u><em>both </em></u>equations is (1, 4)

*** This means that if you graphed both lines on an xy-coordinate plane, the point (1,4) would be the point where the two lines intersect.

That is the third answer shown.

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Answer:

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Step-by-step explanation:

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Help please help me I really need help please help me
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Answer:

  • x = -3

Step-by-step explanation:

<u>Given function:</u>

  • f(x) = x² + 6x + 2

<u>x-coordinate of the vertex is:</u>

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<u>The axis of symmetry is the vertical line that passes through the vertex:</u>

  • x = -3 is the line we need

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