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Vikki [24]
3 years ago
8

What are the solutions of x2 -7x+13 = 0 ?

Mathematics
1 answer:
klasskru [66]3 years ago
3 0

Answer:

x =(7-√-3)/2=(7-i√ 3 )/2= 3.5000-0.8660i

x =(7+√-3)/2=(7+i√ 3 )/2= 3.5000+0.8660i

Step-by-step explanation:

Step by step solution :

Step  1  :

Trying to factor by splitting the middle term

1.1     Factoring  x2-7x+13

The first term is,  x2  its coefficient is  1 .

The middle term is,  -7x  its coefficient is  -7 .

The last term, "the constant", is  +13

Step-1 : Multiply the coefficient of the first term by the constant   1 • 13 = 13

Step-2 : Find two factors of  13  whose sum equals the coefficient of the middle term, which is   -7 .

     -13    +    -1    =    -14

     -1    +    -13    =    -14

     1    +    13    =    14

     13    +    1    =    14

Observation : No two such factors can be found !!

Conclusion : Trinomial can not be factored

Equation at the end of step  1  :

 x2 - 7x + 13  = 0

This may be a lot sorry it is confusing if it is wrong i'm so sorry don't come at me wrong please!

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Step-by-step explanation:

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\huge \bf༆ Answer ༄

Let's solve ~

{ \qquad{ \sf{ \dashrightarrow}}}  \:  \: \sf \:7 \sec(x)  - 7 = 0

{ \qquad{ \sf{ \dashrightarrow}}}  \:  \: \sf \:7 \sec(x)  = 7

{ \qquad{ \sf{ \dashrightarrow}}}  \:  \: \sf \: \sec(x)  = 7 \div 7

{ \qquad{ \sf{ \dashrightarrow}}}  \:  \: \sf \: \sec(x)  = 1

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