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xenn [34]
3 years ago
12

What is the volume of a rectangular prism with length 14 cm, height 4 cm, and width 8 cm? a. 448 cm b. 448 cm² c.448 cm³

Mathematics
2 answers:
wlad13 [49]3 years ago
3 0

Answer:

c

Step-by-step explanation:

notsponge [240]3 years ago
3 0

Answer:V=448 cm units

Step-by-step explanation:

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HELP WILL GIVE BRAINLIEST!!!!!!!!
taurus [48]

Answer:

it appears to be mate, that you are able to buy 6 bananas for your goodness of will.

Step-by-step explanation:

6 bananas (yum) = 3 bucaroos

8 0
3 years ago
Read 2 more answers
Carl collects coins compulsively, but he only likes quarters ($0.25) and dimes ($0.10). Carl currently has 125 coins for a total
Bogdan [553]

Answer:

Carl has 35 dimes and 90 quarters

Step-by-step explanation:

Let the number of quarters be q and the number of dimes be d

Total number of coins is 125;

Hence;

q + d = 125 •••••••••(i)

The total value of quarters present = q * 0.25 = 0.25q

The total value of dimes present = d * 0.1 = 0.1d

Adding both gives the total

0.25q + 0.1d =26 ••••••••(ii)

So we need to solve both equations simultaneously;

From i,

q = 125 - d

Substitute this into ii

0.25(125-d) + 0.1d = 26

31.25 -0.25d + 0.1d = 26

31.25 -26 = 0.25d -0.1d

5.25 = 0.15d

d = 5.25/0.15

d = 35

Recall; q = 125 - d = 125 -35 = 90

7 0
3 years ago
When running a 100 meter race Bill reaches his maximum speed when he is 45 meters from the starting line and 5 seconds have elap
Mkey [24]

Bill's speed is constant after 5 seconds and 45 meters into the race.

Correct responses:

a. Bill's maximum speed is 8 m/s

b. 24 meters

c. 57 meters

<h3>Methods used to calculate speed and distance traveled</h3>

Given parameters are;

The distance of the race = 100 meter

Distance at which Bill reaches maximum speed = 45 meters

Speed Bill maintains after 5 seconds = The maximum speed

Time at which Bill is 85 meters from the starting line = 10 seconds after start

a. Required;

Bill's maximum speed in meters.

Solution:

Distance Bill runs at maximum speed, d = 85 m - 45 m = 40 m

Time at which Bill runs the 40 m at maximum speed, <em>t</em> = 10 s - 5 s = 5 s

Speed = \mathbf{\dfrac{Distance}{Time}}

Therefore;

  • Bill's \  maximum \ speed = \dfrac{40 \ m}{5 \ s} = \underline{8 \ m/s}

b. i. Required:

The distance Bill will run for 3 seconds at the maximum speed;

Solution:

Distance,<em> s</em> = Speed, <em>v</em> × Time, <em>t</em>

<em />

The distance traveled at maximum speed in 3 seconds is therefore;

Distance = 8 m/s × 3 s = 24 m

The distance Bill travels in 3 seconds at the maximum speed is 24 meters.

ii) The distance Bill travels at 8 seconds after start, is given as follows;

Distance traveled in the first 5 seconds = 45 meters

Distance traveled in the next 3 seconds = 24 meters

Therefore;

  • Bill's distance from the starting line 8 seconds after start is 45 meters + 25 meters = <u>69 meters</u>

c. Bill's distance 6.5 seconds after the start of the race is given as follows;

Distance traveled in the first 5 seconds = 45 meters

Distance traveled in the next 1.5 seconds = 1.5 s × 8 m/s = 12 meters

  • Bill's distance from the starting line 6.5 seconds after start of the race = 45 meters + 12 meters = <u>57 meters</u>

Learn more about distance, speed, time, relationship here:

https://brainly.in/question/49075584

6 0
2 years ago
Another math question <br>if you answer I will give you a cookie ​
lina2011 [118]

Answer:

Step-by-step explanation:

Start from left one first

12x & 70

Area as Sum= 12x+70

Area as Product = 12(x+5)

Right side

X & 4

Area as Sum= 5X+20

Area as Product = 5(X+4)

8 0
3 years ago
Please Help , Thank You
olya-2409 [2.1K]
I'll go with A and B 

Hope this helps 
6 0
3 years ago
Read 2 more answers
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