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lozanna [386]
3 years ago
10

Solve 6x2 = 12x − 24

Mathematics
1 answer:
Gennadij [26K]3 years ago
5 0
Assuming the left side is 6x^2,

Divide both sides by 6:

x^{2} = 2x - 4

Set the equation to equal 0 by subtracting both sides by the left side:

x^{2} - 2x + 4 = 0

Use the quadratic formula to solve for x:

x=\frac{-b\pm\sqrt{b^2-4ac}}{2a}

a = 1, b = -2, c = 4

\frac{2\pm\sqrt{-2^2-4(1)(4)}}{2(1)} = \frac{2\pm\sqrt{-12}}{2}

\frac{2\pm\sqrt{-12}}{2} = 1 - i \sqrt{3}, 1 + i\sqrt{3}

x will equal 1 - i sqrt(3) and 1 + i sqrt(3).
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A line segment BK is an angle bisector of ΔABC. A line KM intersects side BC such, that BM = MK. Prove: KM ∥ AB.
weqwewe [10]

Answer:

∠BKM= ∠ABK

Therefore AB ║KM (∵ ∠BKM= ∠ABK  and lies between AB and KM and BK is the transversal line)

m∠MBK ≅ m∠BKM (Angles opposite to equal side of ΔBMK are equal)

Step-by-step explanation:

Given: BK is an angle bisector of Δ ABC. and line KM intersect BC such that, BM = MK

TO prove: KM ║AB

Now, As given in figure 1,

In Δ ABC, ∠ABK = ∠KBC (∵ BK is angle bisector)

Now in Δ BMK, ∠MBK = ∠BKM (∵ BM = MK and angles opposite to equal sides of a triangle are equal.)

Now ∵ ∠MBK = ∠BKM

and  ∠ABK = ∠KBM

∴ ∠BKM= ∠ABK

Therefore AB ║KM (∵ ∠BKM= ∠ABK and BK is the transversal line)

Hence proved.  

8 0
3 years ago
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I need some help; if you don't know the answer, don't answer
ohaa [14]

Answer:

B is the right answer and if you want learn this, than learn algebric expression

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Answer:

\Huge \boxed{x=24}

Step-by-step explanation:

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Combine all like terms.

(-5+ 12- 8)x = -24

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Multiply both sides by -1.

x=24

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At a local track meet, RCMS won 3 blue ribbons than red ribbons. They also won 7 more yellow ribbons than red ribbons. RCMS won
erma4kov [3.2K]
Let no red ribbons=x
no. Of blue ribbons=x+3
No. Of yellow ribb9ns=x+7
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3x=18
X=18/3
X=6

No .of red ribbons=6
No. Of blue ribbons=x+3=9
No. Of yellow ribbons=x+7=13
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