
Let AB be a chord of the given circle with centre and radius 13 cm.
Then, OA = 13 cm and ab = 10 cm
From O, draw OL⊥ AB
We know that the perpendicular from the centre of a circle to a chord bisects the chord.
∴ AL = ½AB = (½ × 10)cm = 5 cm
From the right △OLA, we have
OA² = OL² + AL²
==> OL² = OA² – AL²
==> [(13)² – (5)²] cm² = 144cm²
==> OL = √144cm = 12 cm
Hence, the distance of the chord from the centre is 12 cm.
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Answer:
32.9
Step-by-step explanation:
47% of 70 would be answered by doing the following
0.47 x 70 = 32.9
To convert from a percent into a decimal, divide the percent by a hundred and you will have your decimal.
Answer:
b) -5^x + 3x - 2
Step-by-step explanation:
(f-g) = -5^x - 4 - (-3x - 2) = -5^x - 4 + 3x + 2 = -5^x +3x - 2
therefore, the answer is b) -5^x + 3x - 2
hope this helps! <3
Answer:
The answer is -18 and above (that's negative, basically -17,-16, -15,-14,-13,-12, -11, -10, -9, -8, -7, -6, -5,-4, -3, -2, -1).