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dimulka [17.4K]
3 years ago
11

75 is what percent of 60

Mathematics
1 answer:
VLD [36.1K]3 years ago
7 0
75 is 125% of 60. Hope this helps! :)
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How sensitive to changes in water temperature are coral reefs? To find out, scientists examined data on sea surface temperatures
Oduvanchick [21]

The correlation coefficient tells that every increase in sea surface temperature of one degree Celsius will result in an average of 0.1578 fewer centimeters of coral growth per year.

Using technology

The mean= x bar = 26.4667

The mean = y bar= 0.86

The standard deviation= Sx= 0.2251

The standard Deviation Sy=  0.0438

The Correlation Coefficient= r = -0.8111

The slope= b= r* Sy/Sx= -0.15789

The intercept is 5.0389

(d)<u><em> Every increase </em></u>in sea <u><em>surface temperature</em></u> of one degree Celsius will result in an average of <em><u>0.1578 fewer</u></em> centimeters of <em><u>coral growth</u></em> per year.

Here the independent variable is X the sea surface temperature and dependent variable is the Y coral growth.

As the temperature decreases which is along x- axis the growth increases along y axis.

From the given options the option d is the best answer according to the question given.

The same values are calculated using different technology .

brainly.com/question/24183059

6 0
2 years ago
You deposit $2000 in an account that earns 5% annual interest compounded quarterly Find the balance after five years. Show work.
evablogger [386]
500 , 2000x.05 is 100 10x5 = 500
8 0
3 years ago
A small box of chocolates weighs a fifth a large box of chocolates. The difference in weight between a small box of chocolate an
antoniya [11.8K]

Answer:

4 punds

Step-by-step explanation:

7 0
2 years ago
Find the derivative of sinx/1+cosx, using quotient rule​
Mrrafil [7]

Answer:

f'(x) = -1/(1 - Cos(x))

Step-by-step explanation:

The quotient rule for derivation is:

For f(x) = h(x)/k(x)

f'(x) = \frac{h'(x)*k(x) - k'(x)*h(x)}{k^2(x)}

In this case, the function is:

f(x) = Sin(x)/(1 + Cos(x))

Then we have:

h(x) = Sin(x)

h'(x) = Cos(x)

And for the denominator:

k(x) = 1 - Cos(x)

k'(x) = -( -Sin(x)) = Sin(x)

Replacing these in the rule, we get:

f'(x) = \frac{Cos(x)*(1 - Cos(x)) - Sin(x)*Sin(x)}{(1 - Cos(x))^2}

Now we can simplify that:

f'(x) = \frac{Cos(x)*(1 - Cos(x)) - Sin(x)*Sin(x)}{(1 - Cos(x))^2} = \frac{Cos(x) - Cos^2(x) - Sin^2(x)}{(1 - Cos(x))^2}

And we know that:

cos^2(x) + sin^2(x) = 1

then:

f'(x) = \frac{Cos(x)- 1}{(1 - Cos(x))^2} = - \frac{(1 - Cos(x))}{(1 - Cos(x))^2} = \frac{-1}{1 - Cos(x)}

4 0
3 years ago
I need the measure of
WINSTONCH [101]

Answer:

90-55= 35 degrees

Step-by-step explanation:

5 0
2 years ago
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