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Snezhnost [94]
4 years ago
12

Suppose the total weight of the fish caught stayed the same but instead of 100 fish caught during the weeklong fishing trip,only

10 fish were caught.How would the weight of each fish change.Explain
Mathematics
2 answers:
sasho [114]4 years ago
8 0
The 10 fish would be really big fish???
Likurg_2 [28]4 years ago
6 0
If i understand correctly......

say there were 100 fish each weighs 1 pound

and if there were ten fish each would weigh 10 pounds

But the number of pounds stays the same.

100x1=100 and 10x10=110

I hope I helped!!! 
Please let me know if you have any other questions. 

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Two cards are drawn in succession without replacement from a standard deck of 52 cards. What is the probability that the first c
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Answer:

Recheck your question

Step-by-step explanation:

I think your question should be what is the probability that the second card is a spade given that the first one was a club

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2 years ago
What would a solution set be for x < 2(include at least three values)
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Step-by-step explanation:

Any value less than 2

For example:

-1, 0, 1

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0.4, 0.8, 1.7

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3 years ago
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Dmitrij [34]

Answer:

C x=55

Step-by-step explanation:

the angles of a trianlge add up to 180

the unmarked angle is also 35 because of the same side length

35+35=70

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4 0
3 years ago
Find the mean, range, and interquartile range of the heights of plants given
Artist 52 [7]

Answer:

Mean = 30.9

Range = 80

Interquartile Range = 36

Step-by-step explanation:

The mean of a set of numbers is the sum divided by the number of terms. In other words that means 2, 22, 4, 36, 82, 44, 65, 30, 8, 16 go over a fraction like this. There are 10 numbers here so this is our denominator.

\frac{2+ 22 + 4 + 36 + 82 + 44 + 65 + 30 + 8 + 16}{10}

\frac{309}{10} > 30.9

For the range, all we do is subtract the minimum value from the maximum which is 82 - 2. That gives us 80.

For the IQ Range....

Arrange the terms in ascending order.

2, 4, 8, 16, 22, 30, 36, 44, 65, 82

Then we need to find the median which is the average of the two middle terms.

\frac{22+30}{2} > \frac{2*11 + 30}{2} >\frac{2*11+2*15}{2} > \frac{2 * (11 + 15)}{2} > 11 + 15 > 26

So for the lower half of data 2, 4, 8, 16, 22 we have the median of 8

And for the upper half 30, 36, 44, 65, 82 we have the median of 44.

To find the IQ Range it is the difference between the first quartile (8) and the third (44)

So 44 - 8 = 36

7 0
2 years ago
Read 2 more answers
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