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barxatty [35]
3 years ago
11

What are two negative integers that have the same sum as -2 and -5

Mathematics
1 answer:
Pavlova-9 [17]3 years ago
4 0
-1 and -6 have the same sum as -2 and -5, which is -7
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5+3=4d please help me
ad-work [718]
So the object of this problem is to find out the value of d.

To do this, first think about 5 + 3. This equals 8, right? So the value of d times 4 has to equal 8.

No other number besides 2 would make sense. 2 would equal d because 4 x 2 is 8, and 5 + 3 is 8.

So you would write the answer as:

5+3=4(2)
4 0
3 years ago
Read 2 more answers
How many solutions does this equation have?
IgorLugansk [536]

Answer:

C

Step-by-step explanation:

4 0
3 years ago
Read 2 more answers
PLEASE HELP! I have a deadline tonight ,I have to get this done! thank you!!<br> Two questions (:
Viktor [21]
Both of your answers are correct. In the first equation, if you were to substitute 3 for x, because you have to do exponents first, you have 3^2, which is 9, and 9*6 =54. If you were to substitute -3 for x again you would have to do the exponents first which would be -3^2 which is 9, and 9*6 = 54. 

For the second question, if I substitute 0.75 for t, I get -9 + 18 + 7. This is equal to 16, and therefore the answer would be D. Hope this helps! :D. Let me know if you have questions about my explanation, and feel free to post more questions.
3 0
3 years ago
If someone helps me with dis ill give u brainliest​
jolli1 [7]

Answer:

4 different answers

Step-by-step explanation:

1.

[(24/3) + (5*2^2)] = 28

2.

[(3 + 5) * 2^2 )]/24 = 32/24 = 4/3

3.

[(24/3 + 5)*2^2] = 52

4.

[(3 + 5*2^2)/24] = 23/24

5 0
3 years ago
Read 2 more answers
A rectangular enclosure is to be created using 82m rope.
atroni [7]
Let
x-----> the length of rectangle
y-----> the width of rectangle

we know that 
perimeter of rectangle=2*[x+y]
perimeter of rectangle=82 m
82=2*[x+y]---> divide by 2 both sides---> 41=x+y--> y=41-x---> equation 1

Area of rectangle=x*y
substitute equation 1 in the area formula
Area=x*[41-x]----> 41x-x²

using a graph tool
see the attached figure

the vertex is the point (20.5,420.25)
that means
 for x=20.5 m ( length of rectangle)
the area is 420.25 m²

y=420.25/20.5----> 20.5 m

the dimensions are
20.5 m x 20.5 m------> is a square

the answer part 1) 
<span>the dimensions of the rectangular with Maximum area is a square with length side 20.5 meters
</span>
Part 2)<span>b) Suppose 41 barriers each 2m long, are used instead. Can the same area be enclosed?
</span>divide the length side of the square by 2
so
20.5/2=10.25--------> 10 barriers
the dimensions are 10 barriers x 10 barriers
10 barriers=10*2---> 20 m

the area enclosed with barriers is =20*20----> 400 m²

400 m² < 420.25 m²
so

the answer Part 2) is 
<span>the area enclosed by the barriers is less than the area enclosed by the rope
</span>
Part 3)<span>How much more area can be enclosed if the rope is used instead of the barriers
</span>
area using the rope=420.25 m²
area using the barriers=400 m²

420.25-400=20.25 m²

the answer part 3) is
20.25 m²

6 0
3 years ago
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