<span>In the question "Jane Marko buys a car for $43,900.00. In three years, the car depreciates 48% in value. How much is the car worth in three years", the correct answer is $22,828.00 (option A).
The cost of the car = $43,900.00
Depreciation in value in three years = 48% of $43,900.00 = 0.48 x 43,900.00 = $21,072.00
Value of the car after three years = $43,900 - $21,072 = $22,828.00</span>
Answer:
B. One solution
Step-by-step explanation:
Here are a system of how two equations can be classified ;
• If the gradients are the same but the y-intercepts are different, the system has no solution.
• If the gradients are different, the system has one solution.
• If the gradients are the same and the y-intercepts are the same, the system has infinitely many solutions.
Y= (x/4) + 3
When x =1
y= 13/4
When x=3
y= 15/4
Gradient of Y= (x/4) + 3
=∆y/∆x
= (15/4 - 13/4)/ ( 3-1)
=( 2/4)÷ 2
=( 2/4 ) × (1/2)
= 1/4
-4x + y = 4
When x= 1
Y= 8
When x=3
Y=16
Gradient of -4x + y = 4
=∆y/∆x
= (16 - 8)/(3-1)= 8/2 = 4
Since the gradients are different then the system has one solution.
Answer:
answer is down below
Step-by-step explanation:
2x^2 + 5x + 2 =0
multiply 2x^2 x 2 = 4x^2
find two numbers that multiply together to get 4 and add together to make 5
so 4 and 1.
Put them in back in the equation: 2x^2 + x + 4x + 2
split it up in the middle and factorise
so 2x^2 + x becomes x(2x+1)
and 4x+2 becomes 2(2x+1)
<u>so (x+2)(2x+1) is the answer</u>
Divide each by 2
40= 20
144= 72
Divide by 2 again
20=10
72=36
Divide by 2 one more time
10=5
36=18
Ans= 5:18
