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Arada [10]
3 years ago
15

What is the resistance in a circuit when the current is 0.5 ampere? Ohms​

Mathematics
1 answer:
Ilia_Sergeevich [38]3 years ago
6 0

Answer:

24 Ohms

Step-by-step explanation:

Resistance is a function of amperes. For each amp, there is one and only one value for resistance.

It works the other way, too.

E=IR (well-known relationship). If IR=12, R=12/I

R=E* (1/I)

When the current is 0.5 amp, R=12/0.5 - 24 ohms

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The cost of, y, of a large pizza with x topping from pats pizzeria can be modeled by a linear function. A large pizza with no to
Firdavs [7]

Answer:

The cost would be 22.75

Step-by-step explanation:

To find the cost of each topping, we simply take the excess cost and divide it by the number of toppings. To find the excess cost, take the new cost and subtract the original cost.

17.50 - 14.00 = 3.50

Now divide that by the amount of toppings.

3.50/2 = 1.75

Now we can multiply the new number of toppings by that amount and add the cost of the pizza.

5(1.75) + 14.00

8.75 + 14.00

22.75

3 0
3 years ago
Read 2 more answers
How do you write 5.3 * 104 in standard form?
mixer [17]
Multiply 5.3 by 104.

Answer: 551.2
3 0
2 years ago
9a-18b+21c apply distributive property to factor out gcf of all three terms
horsena [70]
The GCF of the three terms (9a, -18b and 21c) is 3

Rewrite each of the terms so 3 is a factor
9a = 3*3a
-18b = -3*6b
21c = 3*7c

So we can say...
9a - 18b + 21c = 3*3a - 3*6b + 3*7c
9a - 18b + 21c = 3(3a - 6b + 7c)

Answer: 3(3a - 6b + 7c)

If you distribute outer 3 to each of the inner terms and multiply, you'll get the original expression again.

3 0
2 years ago
Read 2 more answers
Consider the sets below. u = {x | x is a real number} a = {x | x is an odd integer} r = {x | x = 3, 7, 11, 27} is r ⊂ a?
-BARSIC- [3]

The correct option is (B) yes because all the elements of set R are in set A.

<h3>What is an element?</h3>
  • In mathematics, an element (or member) of a set is any of the distinct things that belong to that set.

Given sets:

  1. U = {x | x is a real number}
  2. A = {x | x is an odd integer}
  3. R = {x | x = 3, 7, 11, 27}

So,

  • A = 1, 3, 5, 7, 9, 11... are the elements of set A.
  • R ⊂ A can be understood as R being a subset of A, i.e. all of R's elements can be found in A.
  • Because all of the elements of R are odd integers and can be found in A, R ⊂ A is TRUE.

Therefore, the correct option is (B) yes because all the elements of set R are in set A.

Know more about sets here:

brainly.com/question/2166579

#SPJ4

The complete question is given below:
Consider the sets below. U = {x | x is a real number} A = {x | x is an odd integer} R = {x | x = 3, 7, 11, 27} Is R ⊂ A?

(A) yes, because all the elements of set A are in set R

(B) yes, because all the elements of set R are in set A

(C) no because each element in set A is not represented in set R

(D) no, because each element in set R is not represented in set A

8 0
1 year ago
Please answer this below Question # 15
LiRa [457]

Answer:

c. \: 5x - 2y = 10 \\ \:  \:  \:  \:  \:  10x - 4y = 20 \\

7 0
2 years ago
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