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Gelneren [198K]
3 years ago
5

A rectangle has a width of 8 centimeters and an area of 160 square centimeters a similar rectangle has an area of 250 square cen

timeters. What are the dimensions of the larger rectangle?
Mathematics
1 answer:
nirvana33 [79]3 years ago
4 0
We know that
area of rectangle=L*W/2
L  is the length side
W is the width side

smaller rectangle
area=160 cm²
W=8 cm
A=W*L-----> L=A/W
L=160/8----> 20 cm

larger rectangle
 Area=250 cm²

area larger rectangle/area smaller rectangle=[scale factor]²
so
scale factor²=250/160----> 1.5625
scale factor=√1.5625----> scale factor=1.25

the dimension larger rectangle=scale factor*dimension smaller rectangle

L (larger rectangle)=(1.25)*(20)---> 25 cm
W (larger rectangle)=(1.25)*8----> 10 cm

the answer is
<span>the dimensions of the larger rectangle are 10 cm x 25 cm</span>
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<h3>What is unit rate?</h3>

A unit rate means a rate for one of something.

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Answer:

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Step-by-step explanation:

see the attached figure with letters to better understand the problem

Let

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b ---> the base of rectangle in mm

step 1

Find the base of rectangle

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substitute

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step 2

Find the height of rectangle

a=FB+CG+GH ---> by segment addition postulate

substitute the given values

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Find the length sides CG

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substitute the given values

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CG^2=6^2-3^2

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simplify

CG=3\sqrt{3}\ mm

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step 3

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A=ab

we have

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substitute

A=(6+3\sqrt{3})(12)=(72+36\sqrt{3})\ mm^2

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