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3 years ago

PLEASE HELP!!! MIDTERM!!

Mathematics

2 answers:

Paladinen [302]3 years ago

8 0

Answer:

Step-by-step explanation:

2nd answer choice my guy.... Technically B. :33

dusya [7]3 years ago

7 0

Answer:

Not going to explain my work, because I just did. Somehow just now it dissapeared. That's weird, and frustrating, brainly....

I'll make it simple.

3/20 divided by 3 is 3, now multiply by 20 to get x.

3/20 out of X = 9; X = 60.

There you go.

Brainliest, pl0x?

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2 1/4 - 1/15

bogdanovich [222]

Answer:

2 11/60

Step-by-step explanation:

15/60 -4/60=11/60

2+11/60=2 11/60

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Which expression is equivalent to (2^6×2^2)^2? 2^16 2^24 4^16 4^64

Firdavs [7]

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Step-by-step explanation:

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3 years ago

What is the area of the largest rectangle with lower base on the x-axis and upper vertices on the curve y = 27 − x^2? show your

LUCKY_DIMON [66]

Answer:

Option B.

Step-by-step explanation:

The given curve is

$y=27-x^2$

We need to find the area of the largest rectangle with lower base on the x-axis and upper vertices on the curve $y=27-x^2$ .

Let the vertex in quadrant I be (x,y), then the vertex in quadrant II is (-x,y) .

Length of the rectangle = 2x

Width of the rectangle = y

Area of a rectangle is

$Area=Length\times width$

$Area=2x\times y$

Substitute the value of y from the given equation.

$Area=2x(27-x^2)$

$A=54x-2x^3$ .... (1)

Differentiate with respect to x.

$\frac{dA}{dx}=54-6x^2$

Equate $\frac{dA}{dx}=0$ , to find the critical points.

$0=54-6x^2$

$6x^2=54$

Divide both sides by 6.

$x^2=9$

$x=\pm 3$

The value of x can not be negative because side length can not be negative.

Substitute x=3 in equation (1).

$A=54(3)-2(3)^3$

$A=162-54$

$A=108$

The area of the largest rectangle is 108 square units.

Therefore, the correct option is B.

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3 years ago

I need help ASAPPPPPPP!

telo118 [61]

Answer: The first box

Step-by-step explanation:

V represents volume and r represents radius

So V(r) represents the volume of the basketball with respect to radius

6 0

3 years ago