All categories

3 years ago

PLEASE HELP!!! MIDTERM!!

Mathematics

2 answers:

Paladinen [302]3 years ago

8 0

Answer:

Step-by-step explanation:

2nd answer choice my guy.... Technically B. :33

dusya [7]3 years ago

7 0

Answer:

Not going to explain my work, because I just did. Somehow just now it dissapeared. That's weird, and frustrating, brainly....

I'll make it simple.

3/20 divided by 3 is 3, now multiply by 20 to get x.

3/20 out of X = 9; X = 60.

There you go.

Brainliest, pl0x?

You might be interested in

If an employer reduces the working week from 40 hours to 35 hours, with no

tangare [24]

Answer:

14.285714285714 %

Step-by-step explanation:

suppose the weekly payment is of x dollars

Then

Previous payment : $(x/40) per hour

New payment : $(x/35) per hour

Then

The percentage increase in the hourly rate of pay is :

$=\frac{\frac{x}{35} -\frac{x}{40} }{\frac{x}{40} } \times100$

$=\frac{\frac{5x}{1400} }{\frac{x}{40} } \times100$

$=\frac{5x}{1400} \times \frac{40}{x} \times100$

$=\frac{200}{1400} \times100$

$=\frac{1}{7} \times100$

$=14.285714285714$

6 0

2 years ago

What is the distributive prperty to exspress 24+36

Liula [17]

I think it would be 12(2-3)

Hope this helps!

8 0

3 years ago

Charlotte makes crepes using 5/8 cup of milk for every 1/2 cup of flour. She wants to know the amount of milk uses per cup of fl

const2013 [10]

Answer:1 1/4

Step-by-step explanation:

3 0

3 years ago

Read 2 more answers

The nth term of sequence is n2 + 20

saw5 [17]

Answer:

First three terms:

22,24,26

There are 15 terms in the sequence that are 50 or less, yet only 14 if its just less than 50.

7 0

3 years ago

Read 2 more answers

The position, x, of an object is given by the equation x = A + Bt +Ct2, where t refers to time. What are the dimensions of A, B,

Serjik [45]

Answer: Dimensions of A are of length [L]

Dimensions of B are of $LT^{-1}$

Dimensions of C are of $LT^{-2}$

Step-by-step explanation:

The given equation is

$x(t)=A+Bt+Ct^{2}$

Since the dimension on the L.H.S of the equation is [L] , each of the terms on the right hand side should also have dimension of length[L] to be dimensionally valid

Thus

Dimensions of A = [L]

Dimensions of Bt = [L]

$Bt=[L]\\\\$ $[B][T]=[L]$ $\\\\\therefore [B]=LT^{-1}$

Similarly

Dimensions of $Ct^{}2 = [L]$

$Ct^{2}=[L]\\\\[C][T]^{2}=[L]\\\\\therefore [C]=LT^{-2}$

4 0

3 years ago