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Answer:
Option B) 18 is the correct answer.
Step-by-step explanation:
Let n(A) be the shoppers who purchased at an online store
Let n(B) be the shoppers who purchased at a locally-owned store
Let n(C) be the shoppers who purchased at a big-box store
n(A ∩ B) is the shoppers who purchased at an online store and at a locally-owned store
n(B ∩ C) be the shoppers who purchased at a locally-owned store and at a big-box store
n(C ∩ A) is the shoppers who purchased at an online store and at a locally-owned store and at an online store
From the Venn diagram,
n(A) = 109
n(B) = 34
n(C) = 107
n() = 38
n(B ∩ C) = 17
n(C ∩ A) = 57
On Comparing the Venn Diagrams, we could find that shoppers made a purchase at an online store, a locally-owned store, and a big-box store [n( A ∩ B∩ C)] = 18
Answer:
0.1426 = 14.26% probability that at least one of the births results in a defect.
Step-by-step explanation:
For each birth, there are only two possible outcomes. Either it results in a defect, or it does not. The probability that a birth results in a defect is independent of any other birth. This means that the binomial probability distribution is used to solve this question.
Binomial probability distribution
The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.
In which is the number of different combinations of x objects from a set of n elements, given by the following formula.
And p is the probability of X happening.
The proportion of U.S. births that result in a birth defect is approximately 1/33 according to the Centers for Disease Control and Prevention (CDC).
This means that
A local hospital randomly selects five births.
This means that
What is the probability that at least one of the births results in a defect?
This is:
In which
0.1426 = 14.26% probability that at least one of the births results in a defect.