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goldenfox [79]
3 years ago
5

Algebra Help (attatched)

Mathematics
1 answer:
oee [108]3 years ago
3 0
So the y value of the vertex of the parabola that models the data should be the left hand side of the chart; Number of $2 increases in price. So however your graph is, it should make sense. 
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QUESTIONS 1,2,3 PLSSSS (PICTURE ATTACHED) :)
Brums [2.3K]

Answer:

A) 20/6

B)21/16

C)21/10 or 2.1

Step-by-step explanation:

<h2><u><em>EDIT!: someone else who probably has a better understanding than me answered this and I've been doing this all wrong lol please ignore this .w.</em></u></h2>

to find any probability just find the total and then divide that by the number of whatever you're checking for, eg. parkour backgrounds.

A)

7+3+4+6 = 20 total backgrounds

6 parkour backgrounds.

20/6 is your answer.

B)

6 + 10 + 5 = 21 total marbles

10 + 6 = 16 non yellow marbles

21/16 is your answer.

C)

6 + 10 + 5 = 21 total marbles

10 blue marbles

21/10 or 2.1 is your answer.

5 0
3 years ago
Read 2 more answers
A tablet weighs 1.23 pounds. What is its weight written as a mixed number?
garik1379 [7]
If a tablet weighs 1.23 pounds, the weight written as a mixed number would be, 1 as the whole number and 23 is in the hundreds place, so you would write, 1 and 23/100.
3 0
3 years ago
Which number expresses 6.72 as a fraction in simplest form?
Dimas [21]

The number that expresses 6.72 as a fraction is simplest form is...

6.72= 168/25

5 0
3 years ago
I’m getting 9.8 not sure what I’m doing wrong
Afina-wow [57]

Answer: 10

Step-by-step explanation:

it says round to nearest 10 your answer was 9.8 so round to 10.

hope this helps :)

7 0
2 years ago
Find the average value of f over region
yan [13]
The area of D is given by:

\int\limits \int\limits {1} \, dA = \int\limits_0^7 \int\limits_0^{x^2} {1} \, dydx  \\  \\ = \int\limits^7_0 {x^2} \, dx =\left. \frac{x^3}{3} \right|_0^7= \frac{343}{3}

The average value of f over D is given by:

\frac{1}{ \frac{343}{3} }  \int\limits^7_0  \int\limits^{x^2}_0 {4x\sin(y)} \, dydx  = -\frac{3}{343}  \int\limits^7_0 {4x\cos(x^2)} \, dx  \\  \\ =-\frac{3}{343} \int\limits^{49}_0 {2\cos(t)} \, dt=-\frac{6}{343} \left[\sin(t)\right]_0^{49} \, dt=-\frac{6}{343}\sin49
3 0
3 years ago
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