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3 years ago

(3x^3 - 7x^2 + 12) - (3x^3 + 6x^2 + 10x)

1 answer:

5 0

The answer should be B. you combine the like terms. when it is a negative sign in front of the parenthesis, when removing the parenthesis, every term inside the parenthesis need to change sign, negative to positive, positive to negative.

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Find the area of the shape shown below.

SCORPION-xisa [38]

The correct is 40 hope I helped

4 0

3 years ago

Read 2 more answers

Rewrite the following equation in exponential form.

ira [324]

Answer:

5² = 25

Step-by-step explanation:

log5 25 = 2

log(b) (x) = (y)

make b^(y) = (x)

5² = 25

I hope this helps!

5 0

2 years ago

Nadir saves $1 the first day of a month, $2 the second day, $4 the third day, and so on. He continues to double his savings each

Leto [7]

The answer is $16,384. If this helps you please make it brainliest as it helps me out.

128

256

512

1024

2048

4096

8,192

16,384

6 0

3 years ago

(4x + 3) (3x^2 - 5x + 6)

Liula [17]

Answer:

12x^3 - 11x^2 + 9x + 18

Step-by-step explanation:

12x^3 - 20x^2 + 24x + 9x^2 -15x + 18

Combine like terms

12x^3 - 11x^2 + 9x + 18

4 0

3 years ago

part 2. Find the value of the trig function indicated, use for that Pythagorean theorem to find the third side if you need it.

andreev551 [17]

Answer: $\bold{5)\ \cos \theta=\dfrac{\sqrt{11}}{6}\qquad 6)\ \tan \theta =\dfrac{8}{17}\qquad 7)\ \cos \theta = \dfrac{4}{3}\qquad 8)\ \cos \theta = \dfrac{\sqrt{10}}{10}}$

<u>Step-by-Step Explanation:</u>

Pythagorean Theorem is: a² + b² = c² , <em>where "c" is the hypotenuse</em>

$5)\ \cos \theta=\dfrac{\text{side adjacent to}\ \theta}{\text{hypotenuse of triangle}}=\dfrac{3\sqrt{11}}{18}\quad \rightarrow \large\boxed{\dfrac{\sqrt{11}}{6}}$

Note: (15)² + (3√11)² = hypotenuse² → hypotenuse = 18

$6)\ \cos \theta=\dfrac{\text{side adjacent to}\ \theta}{\text{hypotenuse of triangle}}=\dfrac{8}{17}\quad =\large\boxed{\dfrac{8}{17}}$

Note: 8² + 15² = hypotenuse² → hypotenuse = 17

$7)\ \tan \theta=\dfrac{\text{side opposite to}\ \theta}{\text{side adjacent to}\ \theta}=\dfrac{20}{15}\quad \rightarrow \large\boxed{\dfrac{4}{3}}$

Note: hypotenuse not needed for tan

$8)\ \cos \theta=\dfrac{\text{side adjacent to}\ \theta}{\text{hypotenuse of triangle}}=\dfrac{2}{2\sqrt{10}}\quad =\large\boxed{\dfrac{\sqrt{10}}{10}}$

Note: 2² + 6² = hypotenuse² → hypotenuse = 2√10

8 0

2 years ago