Answer:
Find two good points and do rise over run. or you can do the x1 y1 thing
Step-by-step explanation:
Since we are already given the amount of jumps from the first trial, and how much it should be increased by on each succeeding trial, we can already solve for the amount of jumps from the first through tenth trials. Starting from 5 and adding 3 each time, we get: 5 8 (11) 14 17 20 23 26 29 32, with 11 being the third trial.
Having been provided 2 different sigma notations, which I assume are choices to the question, we can substitute the initial value to see if it does match the result of the 3rd trial which we obtained by manual adding.
Let us try it below:
Sigma notation 1:
10
<span> Σ (2i + 3)
</span>i = 3
@ i = 3
2(3) + 3
12
The first sigma notation does not have the same result, so we move on to the next.
10
<span> Σ (3i + 2)
</span><span>i = 3
</span>
When i = 3; <span>3(3) + 2 = 11. (OK)
</span>
Since the 3rd trial is a match, we test it with the other values for the 4th through 10th trials.
When i = 4; <span>3(4) + 2 = 14. (OK)
</span>When i = 5; <span>3(5) + 2 = 17. (OK)
</span>When i = 6; <span>3(6) + 2 = 20. (OK)
</span>When i = 7; 3(7) + 2 = 23. (OK)
When i = 8; <span>3(8) + 2 = 26. (OK)
</span>When i = 9; <span>3(9) + 2 = 29. (OK)
</span>When i = 10; <span>3(10) + 2 = 32. (OK)
Adding the results from her 3rd through 10th trials: </span><span>11 + 14 + 17 + 20 + 23 + 26 + 29 + 32 = 172.
</span>
Therefore, the total jumps she had made from her third to tenth trips is 172.
Answer:
Ethan rollerbladed each day 
kilometers.
Step-by-step explanation:
Given:
Ethan rollerbladed a total of 623 km over d days.
Now, to find the kilometers Ethan rollerblade each day.
Total number of distance rollerbladed = 623 km.
Total number of days = 
<u><em>As, Ethan rollerbladed each day the same distance.</em></u>
Now, to get the distance Ethan rollerbladed in each day we divide total number of distance rollerbladed by total number of days:
Therefore, Ethan rollerbladed each day kilometers.
The answer is when time started it was 5 feet. I took the test and that was right for me
Answer:
a) 388.03
b) 148.49
c) π/8
Step-by-step explanation:
Find the diagram attached
Let the opposite side be y
Given
a) Hypotenuse = 420
theta = 3π/8 rad
theta = 3(180)/8
theta = 67.5degrees
Using the SOH CAH TOA identity
sin theta = opposite/hypotenuse
sin 67.5 = y/420
x = 420sin67.5
x = 420(0.9238)
x = 388.03
Hence the length of the side opposite to the given angle is 388.03
b) Hypotenuse = 420
theta = 3π/8 rad
theta = 3(180)/8
theta = 67.5degrees
Using the SOH CAH TOA identity
cos theta = adjacent/hypotenuse
cos 67.5 = x/420
x = 420cos67.5
x = 420(0.3827)
x = 148.49
Hence the length of the side adjacent to the given angle is 148.49
c) The sum of angle in the triangle is π
Let the measure of the unknown angle be z
z + 3π/8 + π/2 = π
z + 3π+4π/8 = π
z + 7π/8 = π
z = π - 7π/8
z = (8π-7π)/8
z = π/8
Hence the measure of the other acute angle is π/8
