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hammer [34]
3 years ago
10

Make a table of ordered pairs for the equation.

Mathematics
1 answer:
soldier1979 [14.2K]3 years ago
4 0
X y
-2 -3
-1 -1
0 1
1 3
2 5

i can’t graph it, but i hope this helps
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A certain number line uses 20 spaces between consecutive integers.
noname [10]

Answer:

Distance between two consecutive tick marks is 0.05 units.

Step-by-step explanation:

We are given the following information in the question:

It is given that there are 20 ticks between two consecutive number.

Let n and n+1 be the consecutive number.

Formula:

Distance between two ticks =

\displaystyle\frac{\text{Difeerence between the numbers}}{\text{Number of ticks}}\\\\= \frac{(n+1)-n}{20} = \frac{1}{20} = 0.05

Thus, distance between two consecutive tick marks is 0.05 units.

5 0
3 years ago
Hi, I’m really struggling, if anyone knows, please could you help?
pshichka [43]

Answer: a) 26

Step-by-step explanation:

-a would be because as you can see there is a pattern of sticks, so what i did was count up the sticks and i found that there was 6 in the first one. So i counted the second one and it was 10 so i realized that all i had to do was add 4.

and for b i think when it says n it means the nth term which is 4 so i think it means pattern 4 which would be 18 so try that out

hope this helped x

4 0
3 years ago
Jorge took 4 minutes to run 1/2 mile. How long will it take him to run 3 miles?
pychu [463]

Answer:

It will take him 24 minutes

Step-by-step explanation:

If it takes him 4 for minutes to run 1/2 mile, then it will most likely take him 8 minutes for 1 mile. Then you multiply 8 by 3, which gives you 24

3 0
3 years ago
How do you move 0.167 to 2 decimal places
Simora [160]

Answer:

Two Decimal Places Rule #1: If the last digit in 0.167 is less than 5, then remove the last digit. Two Decimal Places Rule #2: If the last digit in 0.167 is 5 or more and the second to the last digit in 0.167 is less than 9, then remove the last digit and add 1 to the second to the last digit.

Step-by-step explanation:

8 0
3 years ago
Read 2 more answers
How many seconds will light leaving Los Angeles take to reach the following locations (a) San Francisco (about 500km), (b) Londo
kondor19780726 [428]

Answer:

a) It takes 0.0017s for the light to reach San Francisco.

b) It takes 0.033s for the light to reach London.

c) It takes 1.334s for the light to reach Mars.

d) It takes 149.7s for the light to reach Venus.

Step-by-step explanation:

Here we can solve this problem by using this following formula:

s = \frac{d}{t}

In which s is the speed(in km/s), d is the distance(in km) and t is the time(in s).

The light speed is 299 792 458 m / s = 299,792.458 km/s, so s = 299,792.458

(a) San Francisco (about 500km)

Find t when d = 500. So

s = \frac{d}{t}

299,792.458 = \frac{500}{t}

299,792.458t = 500

t = \frac{500}{299,792.458}

t = 0.0017s

It takes 0.0017s for the light to reach San Francisco.

b) London(about 10,000km)

Find t when d = 10,000. So

s = \frac{d}{t}

299,792.458 = \frac{10,000}{t}

299,792.458t = 10,000

t = \frac{10,000}{299,792.458}

t = 0.033s

It takes 0.033s for the light to reach London.

(c) the Moon (400,000km)

Find t when d = 400,000. So

s = \frac{d}{t}

299,792.458 = \frac{400,000}{t}

299,792.458t = 400,000

t = \frac{400,000}{299,792.458}

t = 1.334s

It takes 1.334s for the light to reach Mars.

(d) Venus (0.3 A.U. from Earth at its closest approach).

Each A.U. has 149,59,7871 km.

So 0.3 A.U. = 0.3*(149,597,871) = 44,879,361.3. This means that d = 44,879,361.3. So:

s = \frac{d}{t}

299,792.458 = \frac{44,879,361.3}{t}

299,792.458t = 44,879,361.3

t = \frac{44,879,361.3}{299,792.458}

t = 149.7s

It takes 149.7s for the light to reach Venus.

3 0
3 years ago
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