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Elza [17]
3 years ago
5

Hector plans to randomly draw a card from a standard deck of cards, record the result, return the card to the deck, shuffle the

deck, and randomly draw another card. So, he will draw a total of 2 cards.
What is the probability that he draws a 2, and then a 4?
Mathematics
2 answers:
Licemer1 [7]3 years ago
8 0
Well we need to know how many 2's their are and how many 4's there are to know this

Nitella [24]3 years ago
8 0

Answer:

P=0.59%

Step-by-step explanation:

Hello

we need to know that A "standard" deck of playing cards consists of 52 Cards in each of the 4 suits of Spades, Hearts, Diamonds, and Clubs. Each suit contains 13 cards: Ace, 2, 3, 4, 5, 6, 7, 8, 9, 10, Jack, Queen, King, so we have 4 cards with the number 2 , and 4 cards with the number 4

the probability that hector draws a 2 is

p=100%*\frac{4}{52}

p=100%*0.0769

p=7.69%

the probability that on the second attempt to draw a 4 is the same

the total probability is the product of the 2 events

P=100%\frac{4}{52} *\frac{4}{52}

P=100%*0.0059

P=0.59%

have a great day.

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The midpoint of AB is M (6,1). If the coordinates of A are (4, 8), what are the coordinates of B?
geniusboy [140]

Answer:

B = (8,-6)

Step-by-step explanation:

Given

A = (4,8)

M = (6,1) -- Midpoint

Required

Find B

This question will be solved using midpoint formula;

M(x,y) = (\frac{x_1 + x_2}{2},\frac{y_1 + y_2}{2})

Where

A(x_1,y_1) = (4,8)

M(x,y) = (6,1)

Substitute these values in the midpoint formula;

(6,1) = (\frac{4 + x_2}{2},\frac{8+y_2}{2})

By comparison; we have:

\frac{4 + x_2}{2} = 6 -- (1)

\frac{8 + y_2}{2} = 1 -- (2)

Solving (1)

\frac{4 + x_2}{2} = 6

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x_2 = 8

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