Answer:
H(t) = 15 -6sin(2.5π(t -0.5))
Step-by-step explanation:
For midline M, amplitude A, period T and time t0 at which the function is decreasing from the midline, the function can be written as ...
H(t) = M -Asin(2π/T(t -t0))
Using the given values of M=15, A=6, T=0.8 and t0 = 0.5, the equation is ...
H(t) = 15 -6sin(2.5π(t -0.5))
6 lines specifically rotational
= 90°/2
= 45°
x = 45° - 16°
x = 29°
y = 45° + 16°
y = 61°
61° and 29° i guess.
Double of 50 is 100, so 28*100=2800, now half of the answer is 2800/2=1400
The answer is <span>5764801,hope this helps.</span>