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kipiarov [429]
3 years ago
5

Which equations are linear equations written in slope-intercept form?

Mathematics
1 answer:
valina [46]3 years ago
5 0

y = a + bx

Hope this helps!

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Car A began a journey from a point at 9 am, traveling at 30 mph. At 10 am car B started traveling from the same point at 40 mph
mafiozo [28]

At 10 am, Car A is at 30 miles.

Then at 11 am, Car A is at 60 miles and Car B is at 40 miles

At 12 am, Car A is at 90 miles and Car B is at 80 miles

At 1 pm, Car A and B are tied for 120 miles

The very second after Car B passes Car A

Answer: 1:01 pm Car B Passes Car A

5 0
3 years ago
What is the definition of COEFFICIENT?
Lady_Fox [76]
Either the 4th answer or 1st one
5 0
3 years ago
Which expression is undefined?
Mkey [24]

Answer:

D: \frac{3}{(6-6)}

Step-by-step explanation:

Option A equates to -\frac{0}{2}=0

Option B equates to \frac{(-4+0)}{8}=\frac{-4}{8}=-\frac{1}{2}

Option C equates to 0\div11 =0

Option D equates to \frac{3}{(6-6)}=\frac{3}{0} which cannot be defined as division by 0 is impossible

7 0
2 years ago
where does the graph of the function y=tan(x) have asymptotes? at the values of x where cos(x)=0 at the values of x where sin(x)
Gnom [1K]
Answer: at the values where cos(x) = 0

Justification:

1) tan(x) = sin(x) / cos(x).

2) functions have vertical asymptotes at x = a if Limit of the function x approaches a is + or - infinity.

3) the limit of tan(x) approaches +/- infinity where cos(x) approaches 0.

Therefore, the grpah of y = tan(x) has asymptotes where cos(x) = 0.

You can see the asympotes at x = +/- π/2 on the attached graph. Remember that cos(x) approaches 0 when x approaches +/- (n+1) π/2, for any n ∈ N, so there are infinite asymptotes.



7 0
3 years ago
Read 2 more answers
Kenneth ran a marathon (26.2) miles) in 5.5 hours. What was Kenneth’s average speed? (Round your answer to the nearest tenth.)
Serga [27]

Answer:

4.8 miles per hour.

Step-by-step explanation:

Average speed=Total distance/Time taken

=26.2miles/5.5hour

=4.8 miles per hour

3 0
3 years ago
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