Ask question

Ask question

All categories

3 years ago

10

When multiplying a-3 over 2a^2-7a and 4a-14 over a+3, what are the term(s) that can be cancelled

2 answers:

earnstyle [38]3 years ago

8 0

is the equation in the question written like the one in the bottom? Because for me to help you I must confirm what the equation looks like.

$\frac{a-3}{2a^{2} -7a}$ × $\frac{4a-14}{a+3}$

liberstina [14]3 years ago

5 0

<u>Answer:</u>

The term (2a-7) can be cancelled.

<u>Step-by-step explanation:</u>

We are given the following expression and we are to simplify it and see which terms get cancelled out:

$\frac {a-3} {2a^2 - 7a }$ × $\frac { 4a - 14} {a + 3}$

Taking the common terms out to simplify it:

$\frac{a-3}{a(2a-7)}$ × $\frac{2(2a-7)}{a+3}$

Here, the term $(2a-7)$ get cancelled so we are left with:

$\frac{2(a-3)}{a(a+3)}$

You might be interested in

Mrs. Montgomery earns a 6.5% commission on her total sales. Last month, she had sales of $55,780,

Soloha48 [4]

try using the steps in my question i have one just like you

Step-by-step explanation:

4 0

3 years ago

Four students took a national standardized test for which the mean was 500 and the standard deviation was 100. If a student’s z-

murzikaleks [220]

z = (x - 500) / 100

1.75 = (x - 500) / 100

175 = x - 500

675 = x

3 0

3 years ago

Read 2 more answers

?????? help pls lolll

ki77a [65]

Answer is -9

Multiplying by 1/4 is the same as dividing by 4

-36(1/4) = -36/4 = -9

3 0

3 years ago

50 PTS ANSWER ALL <3333333

11Alexandr11 [23.1K]

QUESTION 33

The length of the legs of the right triangle are given as,

6 centimeters and 8 centimeters.

The length of the hypotenuse can be found using the Pythagoras Theorem.

${h}^{2} = {6}^{2} + {8}^{2}$

${h}^{2} = 36+ 64$

${h}^{2} = 100$

$h = \sqrt{100}$

$h = 10cm$

Answer: C

QUESTION 34

The triangle has a hypotenuse of length, 55 inches and a leg of 33 inches.

The length of the other leg can be found using the Pythagoras Theorem,

${l}^{2} + {33}^{2} = {55}^{2}$

${l}^{2} = {55}^{2} - {33}^{2}$

${l}^{2} = 1936$

$l = \sqrt{1936}$

$l = 44cm$

Answer:B

QUESTION 35.

We want to find the distance between,

(2,-1) and (-1,3).

Recall the distance formula,

$d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}$

Substitute the values to get,

$d=\sqrt{( - 1-2)^2+(3- - 1)^2}$

$d=\sqrt{( - 3)^2+(4)^2}$

$d=\sqrt{9+16}$

$d=\sqrt{25}$

$d = 5$

Answer: 5 units.

QUESTION 36

We want to find the distance between,

(2,2) and (-3,-3).

We use the distance formula again,

$d=\sqrt{( - 3-2)^2+( - 3- 2)^2}$

$d=\sqrt{( - 5)^2+( - 5)^2}$

$d=\sqrt{25+25}$

$d=\sqrt{50}$

$d=5\sqrt{2}$

Answer: D

8 0

3 years ago

Read 2 more answers

Im literally sitting here crying my eyes out because i have so much homework due tomorrow someone please just help me with this

skelet666 [1.2K]

Answer:

I'm sorry you have a lot of Homework. All i know is the 1st step... i believe their are 3 steps to this question, I wish you the best of luck my friend!

Step-by-step explanation:

1st step =

x=36

8 0

3 years ago