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2 years ago

The equation y=mx+b is in form

Mathematics

2 answers:

qaws [65]2 years ago

5 0

Answer:

Slope intercept form

m - slope

b - y intercept

hichkok12 [17]2 years ago

3 0

Answer:

slope intercept form

Step-by-step explanation:

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40% discount on all items What is the discount on $60

malfutka [58]

40% is the same as 40/100 so just multiply that with 60

60 x 40/100 = 24

thats how much is taken OFF so

60 is the original price and you get 40% discount off which is $24 on this specific item. how much is the price now?

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2 years ago

Karen had 3 apples. she ate 2. how many will she have left

Vadim26 [7]

Answer:1

Step-by-step explanation:

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3 years ago

I need help with pythagoras’ theorem

fomenos

Answer:

Pythagoras’ theorem is a way to find a side or hypothesis when you have 2 sides.

The formula is: a^2 + b^2 = c^2

a and b are sides

c is the hypothesis

Ex: A triangle has a leg that is 5 inches and a leg that is 7 inches. Find the hypothesis using Pythagoras' theorem.

A leg is another way of saying a side.

5^2 + 7^2 = c^2

25 + 49 = x^2

sqrt(74) = sqrt(x^2)

sqrt(74) inches = hypothesis

Ex: A triangle has a leg that is 9 feet and a hypothesis that is 25 feet. Find the other leg using Pythagoras' theorem.

9^2 + b^2 = 25^2

81 + b^2 - 81 = 625 - 81

sqrt(b^2) = sqrt(544)

b = sqrt(554)

Do you understand more?

4 0

2 years ago

ANSWER QUICK PLEASE THANK YOU!!! 7 1/2 divided by (4 1/2 - 5 1/8)=

DiKsa [7]

Answer:

7 1/2 divided by (4 1/2 - 5 1/8)=-12

Step-by-step explanation:

PLZZ MARK BRAINLIEST!!!!

Answer is -12

8 0

2 years ago

Which is the approximate solution to the system y = 0.5x + 3.5 and y = − 2/3 x + 1/3 shown on the graph? (–2.7, 2.1) (–2.1, 2.7)

AlekseyPX

Answer:

The approximate solution to the system is $(-2.7, 2.1)$ .

Step-by-step explanation:

To solve the system of equations $\begin{bmatrix}y=0.5x+3.5\\ y=-\frac{2}{3}x+\frac{1}{3}\end{bmatrix}$ you must:

$\mathrm{Rationalize\:equations}\\\\\begin{bmatrix}y=\left(\frac{1}{2}\right)x+\left(\frac{7}{2}\right)\\ y=-\frac{2}{3}x+\frac{1}{3}\end{bmatrix}$

$\mathrm{Subsititute\:}y=-\frac{2}{3}x+\frac{1}{3}\\\\\begin{bmatrix}-\frac{2}{3}x+\frac{1}{3}=\frac{1}{2}x+\frac{7}{2}\end{bmatrix}$

$\mathrm{Isolate}\:x\:\mathrm{for}\:-\frac{2}{3}x+\frac{1}{3}=\frac{1}{2}x+\frac{7}{2}\\\\-\frac{2}{3}x=\frac{19}{6}+\frac{1}{2}x\\\\-\frac{7}{6}x=\frac{19}{6}\\\\6\left(-\frac{7}{6}x\right)=\frac{19\cdot \:6}{6}\\\\-7x=19\\\\x=-\frac{19}{7}\approx-2.7$

$\mathrm{For\:}y=-\frac{2}{3}x+\frac{1}{3}\\\\\mathrm{Subsititute\:}x=-\frac{19}{7}\\\\y=-\frac{2}{3}\left(-\frac{19}{7}\right)+\frac{1}{3}\\\\y=\frac{15}{7}\approx 2.1$

The approximate solutions to the system of equations are:

$x=-2.7 ,\:y=2.1$

5 0

3 years ago

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