Answer:
The side of first square =14 units
side of second square =4 units
Step-by-step explanation:
We have given two squares,
A square have all its four sides equal and at right angles.
Let the side of first square be 'a'
and the side of second square be 'b'
Given:
equation:1
equation:2
Solving equation:1
a=10+b equation:3
Putting 'a' in equation:2
Putting 'b' in equation:3
So, the side of first square is 14 units and
side of second square is 4 units
Answer:
x = -1/2 ( 3±sqrt(37))
Step-by-step explanation:
x^2 + 3x − 7 = 0
Add 7 to each side
x^2 + 3x =7
Using complete the square
Taking the coefficient of x
3
Divide by 2
3/2
Square it
(3/2)^2 = 9/4
Add this to each side
x^2 + 3x+ 9/4 = 7+9/4
( x+ 3/2) ^2 = 28/4 + 9/4
( x+ 3/2) ^2 = 37/4
Take the square root of each side
x+3/2 = ±sqrt(37/4)
x+3/2 = ±sqrt(37) / sqrt(4)
x+ 3/2 = ±sqrt(37) / 2
Subtract 3/2 from each side
x = -3/2 ±sqrt(37) / 2
x = -1/2 ( 3±sqrt(37))
Answer:
what is this
Step-by-step explanation:
Answer:
all three sides are congruent.
Step-by-step explanation:
it is equiangular.
sides are equal.
angles are equal.
all three sides are congruent.
