Table A represent a function, and Table B does not.
Why?
Table to be a function, need to satisfy following conditions (look at the .jpeg image attached with this answer):
1. condition: In first circle, EVERY element has to be connected with SOME of the elements in second circle
2. condition: In first circle, there MUSTN'T be an element that has MORE THAN ONE connection with elements in second circle
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Table A satisfies BOTH of these conditions; that is why table A is indeed a function.
Table B satisfies FIRST condition but it does not satisfy the SECOND condition, that is why it is NOT a function.
Answer:
2 ??????
Step-by-step explanation:
sorry if it is wrong
Answer:
SEE attched pic
Step-by-step explanation:
Download symbolab
Answer:
96 in
Step-by-step explanation:
If the midpoints of the sides are joined to form the smaller triangle, then the perimeter of the smaller triangle is half the perimeter of the greater triangle, because the sides of the smaller triangle are midlines of the greater triangle. By the triangle's midline theorem, each triangle's midline is half the side to which this midline is parallel.
So, if the perimeter of 6th triangle is 3 inches, then the perimeter of 5th triangle is 6 inches, the perimeter of 4th triangle is 12 inches, the perimeter of 3rd triangle is 24 in, the perimeter of 2nd triangle is 48 in and the perimeter of the initial triangle is 96 in
Answer:
False
Step-by-step explanation: