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lesantik [10]
3 years ago
13

Three Less Than A Number 15

Mathematics
1 answer:
erica [24]3 years ago
4 0

Answer:

12 ig all i did was subtract 3 from 15

Step-by-step explanation:

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If v(t)=-16t+20, find v(1/2a+1)
Temka [501]

Possible derivation:

d/da(4 - 8 a)

Differentiate the sum term by term and factor out constants:

= d/da(4) - 8 (d/da(a))

The derivative of 4 is zero:

= -8 (d/da(a)) + 0

Simplify the expression:

= -8 (d/da(a))

The derivative of a is 1:

= -8 1

Simplify the expression:

Answer: = -8

4 0
3 years ago
Slope= -1/2, y-intercept = 4​
navik [9.2K]

Answer:

y=-1/2x+4

Step-by-step explanation:

y=mx+b

where m=slope and b=y-intercept

so

y=-1/2x+4

5 0
3 years ago
Angle measure labeled a<br> The arc mesure labeled c
inna [77]

Step-by-step explanation:

angle measure a =48/2=24°

the arc measure =360°-48°=312°

<h3>stay safe healthy and happy.</h3>
5 0
3 years ago
Read 2 more answers
What is the midpoint of C(5,3 and D(-3,-6)
Nat2105 [25]

Answer:

Step-by-step explanation:

Midpoints of two coordinates is expressed using the formula;

M(X, Y) = (x2+x1/2, y2+y1/2)

Given the coordinates  c(5,3) and d(-3,-6)

x1 = 5, y1 = 3, x2 = -3 and y2 = -6

X = x1+x2/2

X = 5+(-3)/3

X = 5-3/2

X = 2/2

X = 1

Also;

Y = y1+y2/2

Y = 3+(-6)/2

Y = 3-6/2

Y = -3/2

Y = -1.5

6 0
3 years ago
part 2. Find the value of the trig function indicated, use for that Pythagorean theorem to find the third side if you need it.​
andreev551 [17]

Answer:  \bold{5)\ \cos \theta=\dfrac{\sqrt{11}}{6}\qquad 6)\ \tan \theta =\dfrac{8}{17}\qquad 7)\ \cos \theta = \dfrac{4}{3}\qquad 8)\ \cos \theta = \dfrac{\sqrt{10}}{10}}

<u>Step-by-Step Explanation:</u>

Pythagorean Theorem is: a² + b² = c²  , <em>where "c" is the hypotenuse</em>

5)\ \cos \theta=\dfrac{\text{side adjacent to}\ \theta}{\text{hypotenuse of triangle}}=\dfrac{3\sqrt{11}}{18}\quad \rightarrow \large\boxed{\dfrac{\sqrt{11}}{6}}

Note: (15)² + (3√11)² = hypotenuse²   →   hypotenuse = 18

6)\ \cos \theta=\dfrac{\text{side adjacent to}\ \theta}{\text{hypotenuse of triangle}}=\dfrac{8}{17}\quad =\large\boxed{\dfrac{8}{17}}

Note: 8² + 15² = hypotenuse²   →   hypotenuse = 17

7)\ \tan \theta=\dfrac{\text{side opposite to}\ \theta}{\text{side adjacent to}\ \theta}=\dfrac{20}{15}\quad \rightarrow \large\boxed{\dfrac{4}{3}}

Note: hypotenuse not needed for tan

8)\ \cos \theta=\dfrac{\text{side adjacent to}\ \theta}{\text{hypotenuse of triangle}}=\dfrac{2}{2\sqrt{10}}\quad =\large\boxed{\dfrac{\sqrt{10}}{10}}

Note: 2² + 6² = hypotenuse²   →   hypotenuse = 2√10

8 0
3 years ago
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