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2 years ago

Please help!!

1 answer:

5 0

Switch y=2x+7 to 2x-y=-7 then multiply that equation by 2 to cancel out the y's. that ends up as 4x-2y=-14 which then you get x=-24. then you substitute x into one of the original equations y= 2(-24)+7 which equals y=-41

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Which functions are the same as their inverse functions

9966 [12]

Answer:

what functions?

Step-by-step explanation:

4 0

2 years ago

A bunch of ballons contains many different colors. red 17 purple 11 orange 3 green 1 yellow 2 What is the probability that a ran

4vir4ik [10]

Answer: 1/2

Step-by-step explanation:

Number of red balloons = 17

Number of purple balloons = 11

Number of orange balloons = 3

Number of green balloons = 1

Number of yellow balloons = 2

Total number of balloons = 34

The probability that a randomly selected balloon will be red will be:

= Number of red balloons/Total number of balloons

= 17/34

= 1/2

5 0

2 years ago

A standard piece of paper is 0.05 mm thick. Let's imagine taking a piece of paper and folding the paper in half multiple times.

tatyana61 [14]

Answer:

(a) $g(n)=0.05\cdot 2^n$

(b) $g^{-1}(n)=\log_{2}20g(n)$

Step-by-step explanation:

Part A

The paper's thickness = 0.05mm

When the paper is folded, its width doubles (increases by 100%).

The thickness of the paper grows exponentially and can be modeled by the function:

$g(n)=0.05(1+100\%)^n\\\\g(n)=0.05\cdot 2^n$

Part B

$g(n)=0.05\cdot 2^n\\2^n=\dfrac{g(n)}{0.05}\\ 2^n=20g(n)\\$Changing to logarithm form, we have:\\\log_{2}20g(n)=n\\$Therefore:\\g^{-1}(n)=\log_{2}20g(n)$

Part C

If the thickness of the paper, g(n)=384,472,300,000 mm

Then:

$g^{-1}(n)=\log_{2}20g(n)\\g^{-1}(n)=\log_{2}20\times 384,472,300,000\\=\dfrac{\log 20\times 384,472,300,000}{\log 2} \\g^{-1}(n)=42.8 \approx 43\\n=43$

You must fold the paper 43 times to make the folded paper have a thickness that is the same as the distance from the earth to the moon.

3 0

2 years ago

Whats an approximate equation of a line that passes through the points (-4.3,2.3) and (1.3,-7.4)

Wewaii [24]

Use the 2 points to find the gradient of the line
Gradient = (y - y1)/(x - x1), y and y1 are the two different y values.
(2.3 - - 7.4)/(-4.3 - 1.3) = -97/56 = -1.732
Note: y and x both come from the same coordinate, and y1 and x1 also come from the same coordinates - (x , y), (x1 , y1)

Use the following to find the equation (x, x1, y, and y1 are not the same as the first part)
y - y1 = m(x - x1)

Where x2 and y2 is an intersection (one of the coordinates you used) and m is the gradient you found.
So...
y - 2.3 = -1.732(x - - 4.3)
You can simplify this if you are required to.

4 0

2 years ago

Solve the system of equations.

Sedaia [141]

Answer:

(6,41)

x=6

y=41

Step-by-step explanation:

I did it algebraically to solve for x and y, and I also graphed both of them and found the point where they intersect. It’s in the image below.

Hope this helps! :)

4 0

2 years ago