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nikitadnepr [17]
3 years ago
15

Write the equation of the line that is parallel to the graph of 3x − y = 5, and whose y-intercept is (0, -7).

Mathematics
1 answer:
zzz [600]3 years ago
4 0

Answer:

y = 3x -7

Step-by-step explanation:

If you use the y = mx + b formula for a line, you know m = 3 because the question says the line is parallel so it must have same slope. In this formula, b is the y intercept and it's already given as -7. Therefore, y = 3x -7.

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Solve the equation for the variable specified. df + 10h = 3 Solve for d. A. d 3= 10h f B. d. 3- 10h f C. d = 3 - 102 D. d = f(3
Nesterboy [21]

Answer:

Step-by-step explanation:

d= (3-10h)/f

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3 years ago
For the polynomial function ƒ(x) = −x6 + 3x4 + 4x2, find the zeros. Then determine the multiplicity at each zero and state wheth
murzikaleks [220]

There is a multiple zero at 0 (which means that it touches there), and there are single zeros at -2 and 2 (which means that they cross). There is also 2 imaginary zeros at i and -i.


You can find this by factoring. Start by pulling out the greatest common factor, which in this case is -x^2.


-x^6 + 3x^4 + 4x^2

-x^2(x^4 - 3x^2 - 4)


Now we can factor the inside of the parenthesis. You do this by finding factors of the last number that add up to the middle number.


-x^2(x^4 - 3x^2 - 4)

-x^2(x^2 - 4)(x^2 + 1)


Now we can use the factors of two perfect squares rule to factor the middle parenthesis.


-x^2(x^2 - 4)(x^2 + 1)

-x^2(x - 2)(x + 2)(x^2 + 1)


We would also want to split the term in the front.


-x^2(x - 2)(x + 2)(x^2 + 1)

(x)(-x)(x - 2)(x + 2)(x^2 + 1)


Now we would set each portion equal to 0 and solve.


First root

x = 0 ---> no work needed


Second root

-x = 0 ---> divide by -1

x = 0


Third root

x - 2 = 0

x = 2


Forth root

x + 2 = 0

x = -2


Fifth and Sixth roots

x^2 + 1 = 0

x^2 = -1

x = +/- \sqrt{-1}

x = +/- i

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