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madreJ [45]
3 years ago
5

(100 points & brainliest!)

Mathematics
1 answer:
Harrizon [31]3 years ago
5 0

Okay so this is a very hard conceptual question. We need to prove that (x, y) is the ordered pair when "f(x) = g(x)".

"f(x) = g(x)" represents the point where the lines share a point or basically the intersection point of the two functions.

To prove that the intersection point is (x, y) let's find the x and y values at the point of intersection.

f(x) ----> the x-value is x and the y-value is f(x)

g(x) -----> the x-value is x and the y-value is g(x)

We know that f(x) = g(x) so we know that the y values match too.

We can also substitute a variable y for f(x) or g(x) (It is simply the y-value when x is plugged in for x. I know it sounds a bit confusing.).

So the solution when f(x) = g(x) is (x, y)!!!

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16: Find the coordinates of the foci and the vertices, the eccentricity, the length of the latus rectum of the Hyperbola y^2-16x
Morgarella [4.7K]

Answer:

Foci (0,\pm\frac{\sqrt{17}}{4})

Vertices:(0,\pm 1)

Eccentricity, e=\frac{\sqrt{17}}{4}

Length of latus rectum=\frac{1}{8}

Step-by-step explanation:

We are given that

y^2-16x^2=1

y^2-\frac{x^2}{(\frac{1}{4})^2}=1

The equation of hyperbola is along y-axis because y is positive

Compare the equation with

y^2/a^2-x^2/b^2=1 (Along y-axis)

We get

a=1, b=1/4

a^2+b^2=c^2

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\frac{16+1}{16}=c^2

c^2=\frac{17}{16}

c=\pm \frac{\sqrt{17}}{4}

Therefore,

The coordinates of foci=(0,\pm c)=(0,\pm\frac{\sqrt{17}}{4})

The coordinated of vertices=(0,\pm a)=(0,\pm 1)

Eccentricity, e=c/a

e=\frac{\frac{\sqrt{17}}{4}}{1}=\frac{\sqrt{17}}{4}

Length of latus rectum=\frac{2b^2}{a}

Length of latus rectum=2\times \frac{1}{16}=\frac{1}{8}

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3 years ago
4/5+5/50<br><br> helllppppp pleaseeee
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THE ASNWER IS 0.9.

HOPES THIS HELPS YOU!!! CAN YOU MARK MINE AS BRAINLIEST????

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