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Setler79 [48]
3 years ago
10

For exponential functions which of the following expression is equal to [f(3)]^4]

Mathematics
1 answer:
Molodets [167]3 years ago
5 0

Answer:

F(3*4)

Step-by-step explanation:

Let\ exponential\ function\ F(x)=a^x\\\\F(3)=a^3\\\\\{F(3)\}^4=\{a^3\}^4\\\\\{F(3)\}^4=a^{3\times 4}...........eq(1)\ \ \ \ \ \ \ \ \ \ \ \ \ \ \ as\ (m^n)^k=m^{nk}\\\\Now\ F(3*4)=a^{3\times 4}.......eq(2)\\\\From\ eq1\ and\ eq2\\\\\{F(3)\}^4=F(3\times 4)\\\\\{F(3)\}^4=F(3*4)

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In a certain year the population of a country reached 321 million. The overall birth rate was births per​ 1000, and the overall
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Answer:

Then it would stay at 321 million

Step-by-step explanation:

if the birth and death rate is both 1000 then nothing will change. Population wise.

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Answer:

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Step-by-step explanation:

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3 years ago
Property in Live Oak County is assessed at $250,000,000. The taxes to be raised are $10,000,000. What is the tax rate?
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3 years ago
Read 2 more answers
PLSSS HELP ME WITH MATH
labwork [276]

Step-by-step explanation:

always remember, equations and inequalities are like a scale with 2 pans (left and right).

a variable is like a placeholder, an empty spot on the pans. and the expressions on both sides are kind of the conditions for the things to put in these empty spots so that the status of the scale stays unchanged.

for an equation the scale has to stay balanced all the time.

and in an inequality one side is heavier that the other (it normally does not matter how much heavier) with "<" or ">" signs, or the scale can be also balanced with "<=" or ">=" signs. just the other side must never be heavier.

A

so, in our case here

2x - 5 = 3

yes, the solution (the ONLY solution, actually) is x = 4. no other value of x allows the scale to be balanced.

2x - 5 >= 3

well, since it is a ">=" sign, we can be lazy and treat it like the equation above, and x = 4 is therefore a valid solution for the inequality too.

but so is every other value of x that makes the left side "heavier". what about e.g. 5 ?

2×5 - 5 >= 3

10 - 5 >= 3

5 >= 3

true, great ! so, e.g. x = 5 is also a valid solution.

what else ?

let's simplify the inequality

2x - 5 >= 3

2x >= 8

x >= 4

so, really every value of x that is greater or equal to 4 is a valid solution for the inequality.

B

-2x - 5 = 3

yes, the solution (the ONLY solution, actually) is x = -4. no other value of x allows the scale to be balanced.

-2x - 5 >= 3

well, since it is a ">=" sign, we can be lazy and treat it like the equation above, and x = -4 is therefore a valid solution for the inequality too.

but so is every other value of x that makes the left side "heavier". what about e.g. -5 ?

-2×-5 - 5 >= 3

remember, -×- = +

10 - 5 >= 3

5 >= 3

true, great ! so, e.g. x = -5 is also a valid solution.

what else ?

let's simplify the inequality

-2x - 5 >= 3

-2x >= 8

x <= -4

a multiplication or division by a negative value flips the inequality sign, because such an operation makes a light weight heavy and a heavy weight light.

so, really every value of x that is less or equal to -4 is a valid solution for the inequality.

3 0
2 years ago
Need help I forgot how to do this ​
Marat540 [252]

Answer:

A.

Step-by-step explanation:

you have to find the discriminant

b²-4ac for each equation

if discriminant < 0 no real solutions because will be negative under the squareroot whhan you try to find the roots

if discriminant = 0 there is only one solution

if discriminant > 0 two real solutions

for your given problems

A. discriminant =(-2)²-4*2*15 will be negative

8 0
3 years ago
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