Let 1st integer be x and next consecutive be x+1
1/2•x + 1/5•(x+1) = 10
x/2 + x/5 + 1/5 = 10
-1/5 -1/5
x/2 + x/5 = 49/5
(x/2)•5/5 + (x/5)•2/2 = 49/5
5x/10 + 2x/10 = 49/5
7x/10 = 49/5
•10 •10
7x = 98
÷7 ÷7
x = 14 --> 1st integer
x+1 = 14+1 = 15 --> next consecutive integer
Hello, again!! :p
I'm not sure about the whole equation because I was taught to solve it in a different way and I got the answer =3 ± i√ 6 ,not a -3.
Sorry, I'm not sure if that was much help!
Answer:
There are no solutions
Step-by-step explanation:
2(x+1)=2x+5
Distribute the values on the left:
2x+2=2x+5
subtract 2x from each side
2x(-2x)+2=2x(-2x)+5
2=5
These value are not equal so there are no solutions
