Question

If you were to solve the following system by substitution, what would be the best

Answer 1

Answer:

x, In the first equation.

Step-by-step explanation:

Answer 2

To solve the two equations simultaneously using the substitution method we need to rearrange one of the equation to make either $'x'$ or $'y'$ the subject. 

We can try in turn rearranging both equations and see which unknown term would have been easier to solve first

Equation $2x+8y=12$

Making $'x'$ the subject
$2x=12-8y$ , dividing each term by 2
$x=6-4y$⇒ (Option 1)

Making $'y'$ the subject
$8y=12-2x$, multiply each term by 8 gives
$y= \frac{12}{8} - \frac{2}{8}x$⇒ (Option 2)

Equation $3x-8y=11$
Making $'x'$ the subject
$3x=11+8y$, divide each term by 3
$x= \frac{11}{3}+ \frac{8}{3}y$ ⇒ (Option 3)

Making $'y'$ the subject
$8y=3x-11$, divide each term by 8
$y= \frac{3}{8}x- \frac{11}{8}$ ⇒ (Option 4)

From all the possibilities of rearranged term, the most efficient option would have been the first option, from equation $2x+8y=12$ with $'x'$ as the subject, $x=6-4y$