QUESTION:
The code for a lock consists of 5 digits (0-9). The last number cannot be 0 or 1. How many different codes are possible.
ANSWER:
Since in this particular scenario, the order of the numbers matter, we can use the Permutation Formula:–
- P(n,r) = n!/(n−r)! where n is the number of numbers in the set and r is the subset.
Since there are 10 digits to choose from, we can assume that n = 10.
Similarly, since there are 5 numbers that need to be chosen out of the ten, we can assume that r = 5.
Now, plug these values into the formula and solve:
= 10!(10−5)!
= 10!5!
= 10⋅9⋅8⋅7⋅6
= 30240.
The answer is x=-2
As you could see, this is a factored function.
The un-factored version is x^2+4x-12
-b/2a=x
-4/2=-2= x of vertex
6 inches squared is your answerStep-by-step explanation:4/2=2 6/2=3
3times 2 equals 6
Answer:
papá fríoStep-by-step explanation:
Answer:
I didn't know if you wanted to get the answer
