Which number is a constant in the algebraic expression? Negative x squared minus 6 y + 13 x + 7 Negative 6 Negative 1 7 13

Mathematics

2 answers:

muminat3 years ago

4 0

Answer:

Step-by-step explanation:

-x^2 -6y+13x+7

The constant is the term with no variable attached to it

7 is the constant

nikitadnepr [17]3 years ago

4 0

Answer:

7 is the constant

Step-by-step explanation:

because -x^2 -6y+13x+7

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Which is the factorization of 8x2 13x – 6? (8x – 3)(x 2) (x – 6)(8x 1) (2x – 2)(4x 3) (4x – 1)(2x 6)

vagabundo [1.1K]

we have

$8x^2+13x - 6$

Equate the function to zero

$8x^2+13x - 6=0$

Group terms that contain the same variable, and move the constant to the opposite side of the equation

$8x^2+13x = 6$

Factor the leading coefficient

$8(x^2+\frac{13}{8}x) = 6$

Complete the square. Remember to balance the equation by adding the same constants to each side.

$8(x^2+\frac{13}{8}x) = 6$

$8(x^2+\frac{13}{8}x+\frac{169}{256}) = 6 +\frac{169}{32} \\ \\ 8(x+\frac{13}{16} )^{2} =\frac{361}{32} \\ \\ (x+\frac{13}{16} )^{2} =\frac{361}{256}\\ \\ (x+\frac{13}{16} ) =(+/-)\sqrt{\frac{361}{256}} \\ \\ (x+\frac{13}{16} ) =(+/-)\frac{19}{16} \\ \\ x1=-\frac{13}{16} +\frac{19}{16} =\frac{6}{16}\\ \\ x2=-\frac{13}{16} -\frac{19}{16}=-2$