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3 years ago

Which number is a constant in the algebraic expression? Negative x squared minus 6 y + 13 x + 7 Negative 6 Negative 1 7 13

Mathematics

2 answers:

muminat3 years ago

4 0

Answer:

Step-by-step explanation:

-x^2 -6y+13x+7

The constant is the term with no variable attached to it

7 is the constant

nikitadnepr [17]3 years ago

4 0

Answer:

7 is the constant

Step-by-step explanation:

because -x^2 -6y+13x+7

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allsm [11]

In decimal form it’s 3.146

4 0

3 years ago

Help me with this pleaae

marissa [1.9K]

Answer:

(D) 30pi inches

Step-by-step explanation:

First, we use the given volume, the given height, and the formula of the volume of a cylinder to find the radius of the base. Then we use the radius of the base to find the circumference of the base.

$volume = \pi r^2 h$

$volume = 6750 \pi~in.^3$

We set the formula equal to the volume and replace h with 30 in.

$\pi r^2 h = 6750 \pi~in.^3$

$\pi r^2 \times 30 ~in. = 6750 \pi~in.^3$

Divide both sides by 30pi in.

$r^2 = 225 ~in.^2$

Take the square root of each side.

$\sqrt{r^2} = \sqrt{225 ~in.^2}$

$r = 15~in.$

The radius of the base is 15 in.

Now we use the radius of the base and the formula of the circumference of a circle to find the answer.

$circumference = 2 \pi r$

$circumference = 2 \pi \times 15~in.$

$circumference = 30 \pi ~in.$

6 0

3 years ago

Please help !!!!!!!! Now asap !!!!!

Andrej [43]

Answer: 4.026 x 10^0, 4.026

Step-by-step explanation:

3 0

1 year ago

Simplify expression X^2+x-2/x^3-x^2+2x-2

professor190 [17]

Answer:

$=\frac {x+2}{x^2+2}$ is the simplest form of given expression.

Step-by-step explanation:

The given question is $\frac{x^2+x-2}{x^3-x^2+2x-2}$

To solve the problem we have to group or split middle term and then factorise

$\frac{x^2+(2x-x)-2}{(x^3-x^2)+(2x-2)}$

Taking $x^2$ common from first two terms of denominator and 2 from next two terms

$= \frac{x^2+2x-x-2}{x^2(x-1)+2(x-1)}$

Now,taking x common from first two terms of numerator and -1 from next two terms and in denominator taking(x-1) common from both terms

$= \frac{ x(x+2)-1(x+2)}{(x-1)(x^2+2)}$

$=\frac{(x+2)(x-1)}{(x-1)(x^2+2)}$

Now cancel out x-1 from both numerator and denominator we get

$=\frac {x+2}{x^2+2}$ is the required simplest form.

7 0

3 years ago

Whats 834×5 plz tell me

amm1812

It is 4170 I believe if my calculations are correct

5 0

3 years ago

Read 2 more answers