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svet-max [94.6K]
2 years ago
15

Solve this quadratic equation using the quadratic formula. 2x^2 - 2x = 0

Mathematics
1 answer:
lakkis [162]2 years ago
6 0

Answer:

27

Step-by-step explanation:

The answer is x=27

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The value of sin-1(1) is negative startfraction pi over 2 endfraction, startfraction -pi over 2 endfraction.

<h3>What is the value of sin (π/2)?</h3>

The value of sin (π/2) is equal to the number 1. The value of the sin-1(1) has to be find out.

Suppose the value of this function is <em>x</em>. Thus,

x=\sin^{-1}(1)

Solve it further,

\sin(x)=(1)              ......1

The value of sin (π/2) and -sin (-π/2) is equal to 1 such that,

\sin\dfrac{\pi}{2}=-\sin\left(-\dfrac{\pi}{2}\right)=1

Put this value in the equation 1,

\sin(x)=\sin\left(\dfrac{\pi}{2}\right)=-\sin\left(-\dfrac{\pi}{2}\right)

Thus, the range will be,

\left(\dfrac{\pi}{2},-\dfrac{\pi}{2}\right)

Thus, the value of sin-1(1) is negative startfraction pi over 2 endfraction, startfraction -pi over 2 endfraction.

Learn more about the sine values here;

brainly.com/question/10711389

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2 years ago
What is the absolute value of -5
vladimir2022 [97]
The absolute value of 2 + 7<span> is 5.</span>
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Answer:

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