Answer:
15
Step-by-step explanation:
To find the 20th term in this sequence, we can simply keep on adding the common difference all the way until we get up to the 20th term.
The common difference is the number that we are adding or subtracting to reach the next term in the sequence.
Notice that the difference between 15 and 12 is 3.
In other words, 12 + 3 = 15.
That 3 that we are adding is our common difference.
So we know that our first term is 12.
Now we can continue the sequence.
12 ⇒ <em>1st term</em>
15 ⇒ <em>2nd term</em>
18 ⇒ <em>3rd term</em>
21 ⇒ <em>4th term</em>
24 ⇒ <em>5th term</em>
27 ⇒ <em>6th term</em>
30 ⇒ <em>7th term</em>
33 ⇒ <em>8th term</em>
36 ⇒ <em>9th term</em>
39 ⇒ <em>10th term</em>
42 ⇒ <em>11th term</em>
45 ⇒ <em>12th term</em>
48 ⇒ <em>13th term</em>
51 ⇒ <em>14th term</em>
54 ⇒ <em>15th term</em>
57 ⇒ <em>16th term</em>
60 ⇒ <em>17th term</em>
63 ⇒ <em>18th term</em>
66 ⇒ <em>19th term</em>
<u>69 ⇒ </u><u><em>20th term</em></u>
<u><em></em></u>
This means that the 20th term of this arithemtic sequence is 69.
The correct answer is:
A line that crosses segment at right angles while dividing the segment in half is called <u>a perpendicular bisector</u>
Step-by-step explanation:
A bisector is a line that divides a line segment in two equal parts. A perpendicular bisector is a line that is perpendicular to given line segment and passes through the mid-point of the line segment. It can also be said as that the line perpendicular to a line segment that divides the lines in half is called the perpendicular bisector.
The correct answer is:
A line that crosses segment at right angles while dividing the segment in half is called <u>a perpendicular bisector</u>
Keywords: Perpendicular, bisector
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Answer:
Area Of a Right Angled∆
=><em><u> </u></em><em><u>1</u></em><em><u>/</u></em><em><u>2</u></em><em><u> </u></em><em><u>x </u></em><em><u>Base </u></em><em><u>x </u></em><em><u>Height</u></em>
Area of a ∆ Using Heron's Formula
=>

Where
- S = Semiperimeter
- a ,b& c = sides of the ∆
Answer:
A) 200 in²
Step-by-step explanation:
Height of the front rectangle
sqrt(6² + 6²)
6sqrt(2)
3 rectangles + 2 triangles
(6×8) + (6×8) + (8×6sqrt(2)) + (2×½×6×6)
132 + 48sqrt(2)
199.8822509939