So 20=2 itmes m2 times 5
5m=5 times m
so
5m=20
5 times m=2 times 2 times 5
divid eboth sides y 5
m=2 times 2
m=4
Consider, please, this solution/explanation:
1. suppose, that number of cars is 'x', numbers of buses is 'y'.
2. according to the condition 'a total of 32', it means that x+y=32. This is the 1st equation.
3. according to the condition in one car are 3x persons, in one bus are 27y persons, and totaly 3x+27y=408 people. This is the 2d equation.
4. if to solve the system of two equations:

Answer: 13 - b., 19 - c.
Answer:
h(g(n))=4n-9
Step-by-step explanation:
h(g(n))=4*g(n)-5 ( we replace n in the formule of h(n) by g(n).
h(g(n))=4(n-1)-5
h(g(n))=4n-4-5
h(g(n))=4n-9
Hope you understand it
Answer:
-1.683
Step-by-step explanation:
Given :
Group 1 :
x1 = 667 ; n1 = 10 ; s1 = 20
Group 2 :
x2 = 679 ; n2 = 14 ; s2 = 15
The test statistic assuming equal variance :
x1 - x2 / √[Sp² * (1/n1 + 1/n2)]
sp² = [(n1 - 1)*s1² + (n2 - 1)*s2²] ÷ (n1 + n2 - 2)
Sp² = [(10 - 1)*20² + (14 - 1)*15²] = 296.59
Test statistic =
(667 - 679)/ √[296.59 * (1/10 + 1/14)]
-12 / 7.1304978
Test statistic = - 1.682