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3 years ago

10

There are 50 homes in a new neighborhood. Every month 3 new homes are built until the neighborhood is complete with a total of 7

7 homes.

1 answer:

ser-zykov [4K]3 years ago

4 0

Answer:

What is the question

Step-by-step explanation:

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Consider the equation below. X2 + y2 − 2x − 4y − z + 5 = 0 reduce the equation to one of the standard forms. Classify the surfac

jeka57 [31]

we are given

$x^2+y^2-2x-4y-z+5=0$

standard form:

We will complete x , y and z square

make all x , y and z terms together

$x^2-2x+y^2-4y-z+5=0$

$x^2-2x+y^2-4y-z=-5$

$x^2-2*1*x+y^2-2*2*y-z=-5$

$x^2-2*1*x+1^2+y^2-2*2*y+2^2-z=-5+1^2+2^2$

$(x-1)^2+(y-2)^2-z=0$

$z=(x-1)^2+(y-2)^2$

surface:

It is an infinite paraboloid

graph:

3 0

3 years ago

With a certain tail wind a jet aircraft arrives at its destination, 1,890 miles away, in 3 hours. Flying against the same wind,

Gelneren [198K]

<span>Find the wind speed and the plane's airspeed.
:
Let s = speed of the plane in still air
Let w = speed of the wind
then
(s-w) = plane speed against the wind
and
(s+w) = plane speed with the wind
:
Change 3 3/8 hrs to 3.375 hrs
:
The trips there and back are equal distance, (1890 mi) write two distance equations
dist = time * speed
:
3.375(s-w) = 1890
3.0(s + w) = 1890

:
It is convenient that we can simplify both these equations:
divide the 1st by 3.375
divide the 2nd by 3
resulting in two simple equations that can be used for elimination of w
s - w = 560
s + w = 630
----------------adding eliminates w, find s
2s = 1190
s =
s = 595 mph is the plane speed in still air
Find w
595 + w = 630
w = 630 - 595
w = 35 mph is the wind spee</span>

3 0

3 years ago

Keeping the properties of exponents in mind to what power must your raise the expression 7 1/2 to get 7 as a result

exis [7]

Answer:

x=2

Step-by-step explanation:

(7^ (1/2))ˣ = 7¹

1/2 *x =1

x =2

3 0

3 years ago

21. For the following exercises, use the descriptions of each pair of lines given below to find the slopes of Line 1 and Line 2.

dybincka [34]

Answer:

The given lines are perpendicular.

Step-by-step explanation:

In the question, two lines are given as line 1 passes through (1,7) and (5,5). Whereas, line 2 passes through (-1,-3) and (1,1).

It is required to find the slope of given lines and figure out whether they are perpendicular, parallel or neither.

To solve this question, first find the slope of both lines. Check if their product is equal to -1, then they are perpendicular. If the slopes are equal the lines are parallel.

Step 1 of 2

Find the slope of first line.

$\begin{aligned}m_{1} &=\frac{5-7}{5-1} \\m_{1} &=\frac{-2}{4} \\m_{1} &=-\frac{1}{2}\end{aligned}$

Step 2 of 2

Find the slope of first line.

$\begin{aligned}&m_{2}=\frac{1-(-3)}{1-(-1)} \\&m_{2}=\frac{4}{2} \\&m_{2}=2\end{aligned}$

And

$\begin{aligned}&m_{1} m_{2}=-\frac{1}{2}(2) \\&m_{1} m_{2}=-1\end{aligned}$

Since, both slopes are reciprocal of each other.

Therefore, the lines are perpendicular.

6 0

1 year ago

Is 6.37492797 a rational number

Aliun [14]

No. An irration number is a fraction, thats a decimal

7 0

3 years ago