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3 years ago

What is 26000 in expanded notation

Mathematics

2 answers:

Cloud [144]3 years ago

4 0

The place value chart can help us to write a number in expanded notation. When we put 26,000 into the place value chart, we can recognize that our number is equal to

2 ten thousands + 6 thousands + 0 hundreds + 0 tens + 0 units

Image is provided

max2010maxim [7]3 years ago

3 0

20000+6000=26000 hope it helps

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Help!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!

shusha [124]

Answer:

Step-by-step explanation:

You need to plug in 3 for all of the x-values

That looks like 2(3)^2 + 5(3) - 9

Then if you simplify it is 2(9) + 15 - 9

Then simplify one last time and you get a final answer of 24

6 0

3 years ago

Read 2 more answers

I will give brainliest to whoever helps me with this question. Also, if you could please explain to me how you solved it I would

KengaRu [80]

Answer:

Step-by-step explanation:

Just as 32, 20, and 40, boom! easy as pie.

8 0

3 years ago

Solve −5+1/4x=3x+6 by graphing.

erma4kov [3.2K]

Answer:

hope its right lol

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3 years ago

In 1984 a locally-owned car company sold 2,743 cars. In 2003, the car sales rose to 4,069. What was the average rate of change f

tatiyna

Answer:

70 cars per year.

Step-by-step explanation:

Given:

In 1984 a locally-owned car company sold 2,743 cars.

In 2003, the car sales rose to 4,069.

Question asked:

What was the average rate of change for the total number of cars sold?

Solution:

In 2003 number of cars sold = 4069

In 1984 number of cars sold = 2743

Change in the number of car sold = 4069 - 2743

= 1326

Now, time interval between 2003 and 1984 = 19

$The\ average\ rate\ of\ change=\frac{Change\ in\ the\ number\ of\ car\ sold}{Time \ interval}$

$=\frac{1326}{19} \\=69.789\\\\=70\ cars\ per\ year\ (approx)$

Thus, the average rate of change for the total number of cars sold is 70 cars per year.

7 0

3 years ago

Katie works part-time at a Fallbrook riding stable she makes $5 an hour for exercising horses and $10 an hour for cleaning stall

Nookie1986 [14]

In order to at least earn $90, Katie can work exercising horses for 6 hours and cleaning stalls for 6 hours.

Step-by-step explanation:

Let hours of exercising horses be x --> $5 per hour = 5x

Let hours of cleaning stalls be y --> $10 per hour = 10y

Total earning = $\geq 90$

Total hours = 12

Equation 1:

5x + 10y = $\geq 90$

Equation 2:

x + y $\leq 12$

1. Multiply equation 2 by -5

x + y $\leq 12$ (*-5)

5x + 10y = $\geq 90$

-5x - 5y $\leq -60$

5x + 10y = $\geq 90$

2. Solve

-5x + 5x -5y + 10y = -60 + 90

5y = 30

y = 6

x + y = 12

x + 6 = 12

x = 6

Therefore, in order to at least earn $90, Katie can work exercising horses for 6 hours and cleaning stalls for 6 hours.

Keywords: Simultaneous, hours, equations

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3 0

4 years ago