Step-by-step explanation:
<h3>
<em><u>Given</u></em><em><u>:</u></em></h3>
Length of the rectangle = 6.5 m
Width of the rectangule = 7.3 m
<h3>
<em><u>Then</u></em><em><u>:</u></em></h3>
<u>First</u><u> </u><u>case</u><u>,</u>
Area of the rectangle
= length × width
= 6.5 m × 7.3 m
= <em><u>47.45</u></em><em><u> </u></em><em><u>s</u></em><em><u>q</u></em><em><u>.</u></em><em><u>m</u></em><em><u> </u></em><em><u>(</u></em><em><u>Ans</u></em><em><u>)</u></em><em><u>(</u></em><em><u>i</u></em><em><u>)</u></em>
<u>Second</u><u> </u><u>case</u><u>,</u>
Perimeter of the rectangle
= 2(length + width)
= 2(6.5 + 7.3)m
= 2 × 13.8 m
= <em><u>27</u></em><em><u>.</u></em><em><u>6</u></em><em><u> </u></em><em><u>m</u></em><em><u> </u></em><em><u>(</u></em><em><u>Ans</u></em><em><u>)</u></em><em><u>(</u></em><em><u>ii</u></em><em><u>)</u></em>
0.00067=67X10^5 so
67X10^5-2.3X10^5
64.7X10^5 which can be expressed as:
6.47X10^6
(not sure if it matters to you or not, but technically we only had two significant figures so it should be rounded to 6.5X10^6)
So i think in the school there may be 4800 in the school. Hope this helps
