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Darya [45]
2 years ago
12

9/14 write as a fraction

Mathematics
1 answer:
Nina [5.8K]2 years ago
7 0

Answer:

Hi. 9/14 is a fraction already. Maybe you meant decimal?

Step-by-step explanation:


You might be interested in
one container holds a 1 7/8 quarts of water and a second container holds 5 3/4 quarts of water. how many more quarts of water do
dimulka [17.4K]
So lets solve this!

Quarts of water 1st container holds= 17/8

Quarts of water 2nd container holds= 5 3/4

Quarts of water does the second container holds than the first container=?

First of all we need to change 5 3/4 into an improper fraction

5 3/4= 23/4

Secondly, we need to find the LCM of 17/8 and 23/4

LCM:

17/8= 51/24

23/4= 138/24

So now we have got both of the LCM's 

Quarts of second container holds the first container= 23/4 - 138/24=87/24

Your answer is 87/24

Hope this Helps!




8 0
3 years ago
1. Susan’s art class is 9 hours long. How long is her class in minutes?
erastova [34]
1. 9(60) = 540 minutes.

2. There is 0.5 pints = 1 cup, so three cups. :)

3. 4(2) = 8 pints.

4. 1,00 millimeters = 1 meter, so 9 meters. 
Hope it helps! :)
4 0
3 years ago
What's 17x=18(1/3) ?
Mariulka [41]
<span>17x=18(1/3)
17x = 6
    x = 6/17

hope it helps</span>
7 0
2 years ago
Find the taylor series for f(x) centered at the given value of a. [assume that f has a power series expansion. do not show that
RUDIKE [14]

The taylor series for the f(x)=8/x centered at the given value of a=-4 is -2+2(x+4)/1!-24/16 (x+4)^{2}/2!+...........

Given a function f(x)=9/x,a=-4.

We are required to find the taylor series for the function f(x)=8/x centered at the given value of a and a=-4.

The taylor series of a function f(x)=f(a)+f^{1}(a)(x-a)/1!+ f^{11}(a)(x-a)^{2} /2! +f^{111}(a)(x-a)a^{3}/3!+..........

Where the terms in f prime f^{1}(a) represent the derivatives of x valued at a.

For the given function.f(x)=8/x and a=-4.

So,f(a)=f(-4)=8/(-4)=-2.

f^{1}(a)=f^{1}(-4)=-8/(-4)^{2}

=-8/16

=-1/2

The series of f(x) is as under:

f(x)=f(-4)+f^{1}(-4)(x+4)/1!+  f^{11}(-4)(x+4)^{2}/2!.............

=8/(-4)-8/(-4)^{2} (-4)(x+4)/1!+  24/(-4)^{3} (-4)(x+4)^{2}/2!.............

=-2+2(x+4)/1!-24/16 (x+4)^{2}/2!+...........

Hence the taylor series for the f(x)=8/x centered at the given value of a=-4 is -2+2(x+4)/1!-24/16 (x+4)^{2}/2!+...........

Learn more about taylor series at brainly.com/question/23334489

#SPJ4

3 0
1 year ago
Find X. Round to the nearest tenth if necessary.
storchak [24]

Answer:

3.2

Step-by-step explanation:

If there are 2 secont lines intersecting inside a circle like the picture shown, then the theorem tells us that <em>"the product of 2 segments of one secant line is equal to the product of 2 segments of other secant line"</em>

<em></em>

Thus, we can say that:

x * 10 = 8 * 4

10x = 32

x = 32/10

x = 3.2

3 0
3 years ago
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