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4 years ago

Which graphs show continuous data? Select each correct answer. 50 points

Mathematics

2 answers:

mixer [17]4 years ago

8 0

Answer:

The answer is B and C

Step-by-step explanation:

I KNOW

postnew [5]4 years ago

5 0

Answer:

Option 1 and 3 are continuous graph.

Step-by-step explanation:

We have been given the four graphs we need to tell which one among these given graphs is continuous

Option 1 is continuous since, there is no break in the graph and points are joint that is a straight line.

Option 2 is discrete graph it is not continuous because these are points which are not joint.

Option 3 is continuous since, there is no break in the graph and points are joint that is a straight line.

Option 4 Option 2 is discrete graph it is not continuous because these are points which are not joint.

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20% of US High School teens vape. A local High School has implemented campaigns to reduce vaping among students and believes tha

zaharov [31]

Answer:

10.93% probability of observing 51 or fewer vapers in a random sample of 300

Step-by-step explanation:

I am going to use the normal approximation to the binomial to solve this question.

Binomial probability distribution

Probability of exactly x sucesses on n repeated trials, with p probability.

Can be approximated to a normal distribution, using the expected value and the standard deviation.

The expected value of the binomial distribution is:

$E(X) = np$

The standard deviation of the binomial distribution is:

$\sqrt{V(X)} = \sqrt{np(1-p)}$

Normal probability distribution

Problems of normally distributed samples can be solved using the z-score formula.

In a set with mean $\mu$ and standard deviation $\sigma$ , the zscore of a measure X is given by:

$Z = \frac{X - \mu}{\sigma}$

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

When we are approximating a binomial distribution to a normal one, we have that $\mu = E(X)$ , $\sigma = \sqrt{V(X)}$ .

In this problem, we have that:

$n = 300, p = 0.2$

$\mu = E(X) = np = 300*0.2 = 60$

$\sigma = \sqrt{V(X)} = \sqrt{np(1-p)} = \sqrt{300*0.2*0.8} = 6.9282$

What is the approximate probability of observing 51 or fewer vapers in a random sample of 300?

Using continuity corrections, this is $P(X \leq 51 + 0.5) = P(X \leq 51.5)$ , which is the pvalue of Z when X = 51.5 So

$Z = \frac{X - \mu}{\sigma}$

$Z = \frac{51.5 - 60}{6.9282}$

$Z = -1.23$

$Z = -1.23$ has a pvalue of 0.1093.

10.93% probability of observing 51 or fewer vapers in a random sample of 300

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4 years ago

Read 2 more answers

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Step one: set the base of each term to be the same (10)
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