Multiply -12 to each of the terms (make sure to carry the negative!)
-36a - 24b + 12 will be your final answer :)
Answer:

Step-by-step explanation:
![\sf{ [ (4 \frac{1}{6} + 2 \frac{1}{3} ) \div 4 \frac{1}{3}] - 1\frac{1}{2} }](https://tex.z-dn.net/?f=%20%5Csf%7B%20%5B%20%284%20%5Cfrac%7B1%7D%7B6%7D%20%20%2B%202%20%5Cfrac%7B1%7D%7B3%7D%20%29%20%20%5Cdiv%204%20%5Cfrac%7B1%7D%7B3%7D%5D%20-%20%201%5Cfrac%7B1%7D%7B2%7D%20%7D)
Convert the mixed numbers into improper fraction
![\longrightarrow{ \sf{ [ ( \frac{25}{6} + \frac{7}{3} ) \div \frac{13}{3}] - \frac{3}{2}}}](https://tex.z-dn.net/?f=%20%5Clongrightarrow%7B%20%5Csf%7B%20%5B%20%28%20%5Cfrac%7B25%7D%7B6%7D%20%20%2B%20%20%5Cfrac%7B7%7D%7B3%7D%20%29%20%5Cdiv%20%20%5Cfrac%7B13%7D%7B3%7D%5D%20-%20%20%5Cfrac%7B3%7D%7B2%7D%7D%7D%20)
Add the fractions : 25 / 6 and 7 / 3
While performing addition or subtraction of unlike fractions, you have to express the given fractions into equivalent fractions of common denominator and add or subtract as we do with like fraction.
To do so, first take the L.C.M of 6 and 3 which results to 6
![\longrightarrow\sf{ [( \frac{25 + 7 \times 2}{6} ) \div \frac{13}{3} ] - \frac{3}{2}}](https://tex.z-dn.net/?f=%20%20%5Clongrightarrow%5Csf%7B%20%5B%28%20%5Cfrac%7B25%20%2B%207%20%5Ctimes%202%7D%7B6%7D%20%29%20%5Cdiv%20%20%5Cfrac%7B13%7D%7B3%7D%20%5D%20-%20%20%5Cfrac%7B3%7D%7B2%7D%7D%20)
![\longrightarrow{ \sf{ [( \frac{25 + 14}{6} ) \div \frac{13}{3} ] - \frac{3}{2} }}](https://tex.z-dn.net/?f=%20%5Clongrightarrow%7B%20%5Csf%7B%20%5B%28%20%5Cfrac%7B25%20%2B%2014%7D%7B6%7D%20%29%20%20%5Cdiv%20%20%5Cfrac%7B13%7D%7B3%7D%20%20%5D%20-%20%20%5Cfrac%7B3%7D%7B2%7D%20%7D%7D)
![\longrightarrow{ \sf{ [ \frac{39}{6} \div \frac{13}{3}] - \frac{3}{2} }}](https://tex.z-dn.net/?f=%20%5Clongrightarrow%7B%20%5Csf%7B%20%5B%20%5Cfrac%7B39%7D%7B6%7D%20%20%5Cdiv%20%20%5Cfrac%7B13%7D%7B3%7D%5D%20-%20%20%5Cfrac%7B3%7D%7B2%7D%20%7D%7D)
Multiply the dividend by the reciprocal of the divisor.
Reciprocal of any number or fraction can be obtained by interchanging the position of numerator and denominator
![\longrightarrow{ \sf{ [ \frac{39}{6} \times \frac{3}{13} ] - \frac{3}{2}}}](https://tex.z-dn.net/?f=%20%5Clongrightarrow%7B%20%5Csf%7B%20%5B%20%20%5Cfrac%7B39%7D%7B6%7D%20%20%5Ctimes%20%20%5Cfrac%7B3%7D%7B13%7D%20%5D%20-%20%20%5Cfrac%7B3%7D%7B2%7D%7D%7D%20)
To multiply one fraction by another, multiply the numerators for the numerator and multiply the denominators for its denominator and reduce the fraction obtained after multiplication into lowest term
![\longrightarrow{ \sf{ [ \frac{39 \times 3}{6 \times 13} ] - \frac{3}{2}}}](https://tex.z-dn.net/?f=%20%5Clongrightarrow%7B%20%5Csf%7B%20%5B%20%20%5Cfrac%7B39%20%5Ctimes%203%7D%7B6%20%5Ctimes%2013%7D%20%5D%20-%20%20%5Cfrac%7B3%7D%7B2%7D%7D%7D%20)
![\longrightarrow{ \sf{ [ \frac{117}{78} ] - \frac{3}{2} }}](https://tex.z-dn.net/?f=%20%5Clongrightarrow%7B%20%5Csf%7B%20%5B%20%20%5Cfrac%7B117%7D%7B78%7D%20%20%5D%20-%20%20%5Cfrac%7B3%7D%7B2%7D%20%7D%7D)

While performing the addition or subtraction of like fractions , you just have to add or subtract the numerator respectively in which the denominator is retained same

Subtract 3 from 3

Divide 0 by 2

Hope I helped!
Best regards!
Set up a x/100 = (14-48)/48 = -34/48 Multiply the cross 48x = -3400 x = 70.8333 so around -70.83% change
Answer: The determinant of the coefficient matrix is -15 and x = 3, y = 4, z = 1.
Step-by-step explanation: The given system of linear equations is :

We are given to find the determinant of the coefficient matrix and to find the values of x, y and z.
The determinant of the co-efficient matrix is given by

Now, from equations (ii) and (iii), we have

Substituting the value of y and z from equations (iv) and (v) in equation (i), we get

From equations (iv) and (v), we get

Thus, the determinant of the coefficient matrix is -15 and x = 3, y = 4, z = 1.
A
Subtract 32 from both sides first, then divide both sides by 9/5