Answer:
0.2081 = 20.81% probability that at least one particle arrives in a particular one second period.
Step-by-step explanation:
In a Poisson distribution, the probability that X represents the number of successes of a random variable is given by the following formula:

In which
x is the number of sucesses
e = 2.71828 is the Euler number
is the mean in the given interval.
Over a long period of time, an average of 14 particles per minute occurs. Assume the arrival of particles at the counter follows a Poisson distribution. Find the probability that at least one particle arrives in a particular one second period.
Each minute has 60 seconds, so 
Either no particle arrives, or at least one does. The sum of the probabilities of these events is decimal 1. So

We want
. So
In which


0.2081 = 20.81% probability that at least one particle arrives in a particular one second period.
Answer:
No solution
Step-by-step explanation:
Simplify the equation to solve for x.
-9(x+6)=-9x+108 Distribute
-9x-54=-9x+108 Combine like terms
+9x +9x
0-54=108 Combine like terms
+54 +54
0=162 No solution
Answer:A
Step-by-step explanation:The answer is A because if you divide the numbers equally, then you will get 1
Answer:
hi how are you also this is rlly easy
Step-by-step explanation:
Answer:
y
=1
/3
x
+
14
/3
Step-by-step explanation: