(−0.0081p)(t)=(15000)(2.718282)
Step 1: Divide both sides by -0.0081t.
−0.0081pt
−0.0081t
=
40774.227427
−0.0081t
p=
−40774.227427
0.0081t
Answer:
p=
−40774.227427
0.0081t
Let
be the speed of train A, and let's set the origin in the initial position of train A. The equations of motion are

where
are the positions of trains A and B respectively, and t is the time in hours.
The two trains meet if and only if
, and we know that this happens after two hours, i.e. at 

Solving this equation for v we have

So, train A is travelling at 105 km/h. This implies that train B travels at

Answer:
Step-by-step explanation:
7619 / 7
= 1088 remainder 3.
Slope intercept form: y=
−5
7
x+5
The graphing points would be (0,5)(7,0)
Answer:
Undefined
Step-by-step explanation:
This is horizontal line, so the slope is undefined.