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garri49 [273]
2 years ago
10

Find f(g(x)) f(x)=2x-5 , g(x)=4x+3

Mathematics
1 answer:
hichkok12 [17]2 years ago
4 0

Set the composite results function.

\boldsymbol{f(g(x)) }

Evaluate f(g(x)) by substituting the value of g into f.

\boldsymbol{2(4x+3)-5}

Simplify each term.

Apply the distributive property.

  • \boldsymbol{f(4x+3)=2(4x)+2\cdot3-5 }

Multiply 4 by 2.

  • \boldsymbol{f(4x+3)=8x+2\cdot3-5 }

Multiply 2 by 3.

  • \boldsymbol{f(4x+3)=8x+6-5 }

Subtract 5 from 6.

  • \boldsymbol{f(4x+3)=8x+1 }

\red{\boxed{\green{\boxed{\boldsymbol{\purple{Pisces04}}}}}}

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Need help for number 4 please
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Answer:

Step-by-step explanation:

4) ΔSTW ≅ ΔBFN . So, corresponding parts of congruent triangles are congruent.

a) BN = SW                                        d) m∠W = m∠N

  BN = 9 cm                                           m∠W = 82°

b) TW = FN                                        e) m∠B = m∠S

TW = 14 cm                                            m∠B = 67°

c) BF = ST                                          f) m∠B + m∠N + m∠F = 180°

  BF = 17 cm                                                 67 + 82 + m∠F = 180

                                                                            149 + m∠F = 180

                                                                                     m∠F = 180 - 149

                                                                                      m∠F = 31°          

5) ΔUVW ≅ ΔTSR

UV = TS

12x - 7 = 53

   12x   = 53+7

   12x = 60

      x = 60/12

      x = 5

UW =TR

3z +14 = 50

    3z = 50 - 14

   3z = 36

     z = 36/3

    z = 12

SR =VW

5y - 33 = 57

     5y = 57 + 33

     5y = 90

       y = 90/5

       y = 18

7) ΔPHS ≅ ΔCNF

∠C = ∠P

4z - 32 = 36

      4z = 36 + 32

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        z = 68/4

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∠H = ∠N

6x - 29 = 115

  6x     = 115 + 29

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       x = 24

∠P + ∠H + ∠S = 180   {Angle sum property of triangle}

36 +115 + ∠S = 180

      151   + ∠S = 180

                ∠S = 180 - 151

               ∠S = 29°

∠F = ∠S

3y - 1 = 29

   3y = 29 + 1

  3y = 30

    y = 30/3

    y = 10

8) ΔDEF ≅ ΔJKL

DE = 18    ;  EF = 23

DF = 9x - 23

JL= 7x- 11

DF = JL           {Corresponding parts of congruent triangles}

      9x - 23 = 7x - 11

9x  - 7x - 23 = -11

        2x - 23 = -11

               2x = -11 + 23

               2x = 12

                 x = 12/2

                x = 6      

JK   = DE           {Corresponding parts of congruent triangles}

3y - 21  = 18

       3y = 18 + 21

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         y = 39/3

        y = 13

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