Kepler believed in the Copernican system and sought the key to reconciling Tycho’s observations with a heliocentric model for the solar system. In addition to his mathematical genius, his philosophical contribution was huge - as described by Einstein: "[Kepler] had to realize clearly that logical-mathematical theorizing, no matter how lucid, could not guarantee truth by itself; that the most beautiful logical theory means nothing in natural science without comparison with the exactest experience. Without this philosophical attitude, his work would not have been possible." (from the introduction Einstein wrote for Baumgard & Callan's 'Johannes Kepler: Life and Letters' (1953)). Kepler's focus on fitting the exact observations from Tycho led him to abandon the idea that the planets had to move on combinations of circles, a bit of logical-mathematical theorizing that had held sway for 1800 years!
Answer:
x = 11
Step-by-step explanation:
right triangle ABC
using Pythagoras' identity
BC² = 7² + 24² = 49 + 576 = 625 ( take square root of both sides )
BC =
= 25
Since the triangles are congruent then corresponding sides are congruent.
ST = BC , that is
3x - 8 = 25 ( add 8 to both sides )
3x = 33 ( divide both sides by 3 )
x = 11
9514 1404 393
Answer:
38
Step-by-step explanation:
The graph shows all of the sides of the figure aligned with the axes except side ST. Its length can be found using the distance formula:
d = √((x2 -x1)² +(y2 -y1)²)
d = √((7 -(-5))² +(-2 -3)²) = √(144 +25) = 13
Then the perimeter is the sum of the side lengths:
13 + 4 + 12 + 9 = 38
The perimeter of STUV is 38 units.
Answer:
Truck can safely carry <em>2310 pounds </em> of cargo.
Step-by-step explanation:
Given the safety limit of weight to cross the bridge safely is 4 tons.
1 ton is equal to 2000 pounds.
so, 4 tons are equal to 2000
4 = 8000 pounds
Now, given that
weight of empty truck and driver = 5690 pounds
To find:
Weight of cargo that the truck can safely carry ?
Solution:
Total weight of the truck is actually the combined weight of the empty truck, the drive and the cargo carried in it.
So, Total Weight allowed = 8000 pounds = 5690 pounds + Weight of Cargo
Weight of Cargo = 8000 - 5690 pounds
Weight of Cargo = <em>2310 pounds</em>
Truck can safely carry <em>2310 pounds </em> of cargo.
Let the length be x and the width be y:
Area=x*y=600
thus
x=600/y
Perimeter=2(L+W)
100=2(x+y)
substituting the value of x we obtain:
100=2(600/y+y)
solving for y we shall have:
50=600/y+y
50y=600+y^2
thus
y^2-50y+600=0
solving the quadratic we obtain:
y=20 or y=30
thus the length=30 ft and the width=20 ft