The circumference of the circle is equal to the perimeter of the triangle, then the area of the circle is 12 square units. Option D is correct.
<h3>What is a circle?</h3>
It is a locus of a point drawn equidistant from the center. The distance from the center to the circumference is called the radius of the circle.
A triangle has sides that measure 2 units, 5 units, and 5.39 units.
The circumference of the circle is equal to the perimeter of the triangle. Then the radius of the circle will be
![2 \pi r = 5 + 2 +5.39\\\\r = 1.97](https://tex.z-dn.net/?f=2%20%5Cpi%20r%20%20%3D%20%205%20%2B%202%20%2B5.39%5C%5C%5C%5Cr%20%3D%201.97)
Then the area of the circle will be
![\rm Area \ of \ circle = \pi r^2\\\\Area \ of \ circle = \pi 1.97^2\\\\Area \ of \ circle = 12.21 \approx 12](https://tex.z-dn.net/?f=%5Crm%20Area%20%5C%20of%20%5C%20circle%20%20%3D%20%20%5Cpi%20r%5E2%5C%5C%5C%5CArea%20%5C%20of%20%5C%20circle%20%20%3D%20%20%5Cpi%201.97%5E2%5C%5C%5C%5CArea%20%5C%20of%20%5C%20circle%20%20%3D%20%2012.21%20%5Capprox%2012)
The area of the circle is 12 square units.
More about the circle link is given below.
brainly.com/question/11833983
Answer: 26
Step-by-step explanation:
divide 19.5 by 3/4 (0.75)
Answer:
17. D
18. C
Step-by-step explanation:
For both of these questions, you only need a general understanding of what rotation, translation, and dilation do. That is sufficient to let you choose the correct answer.
<h3>17.</h3>
The coordinates of Y are both negative, so it is a point in quadrant III on the graph. Rotating a point in quadrant III 270° clockwise will rotate it through quadrants II and I to quadrant IV, where it will be to the right and below the origin. Translation 9 units right and 5 units down will put it farther to the right and farther below the origin, still in quadrant IV.
As you know, translation right 9 units adds 9 to the x-coordinate. Translation down 5 units subtracts 5 from the y-coordinate. That means the coordinates of Y' must have x > 9 and y < -5. There is only one answer choice like that:
D. Y'(11, -8)
__
<h3>18.</h3>
Dilation about the origin multiplies each coordinate by the scale factor. It does not change the quadrant of a point on the graph. The original coordinates of R are (negative, positive), so it is in quadrant II. The dilated point will still be in quadrant II, but will be closer to the origin. Both coordinate values will change.
R' = (1/3)R = (1/3)(-2, 3) = (-2/3, 3/3)
R' = (-2/3, 1) . . . . . matches choice C
667.302 would be the correct answer, I did it in a calculator
C is the answer because if you distributed the P separately to each term (10 and -2) you would get 10P and -2P