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iogann1982 [59]
3 years ago
8

How do you solve...3c^3d/9cd^-1

Mathematics
1 answer:
Maksim231197 [3]3 years ago
4 0
<u>  3c³d  </u>  = <u>c²d²</u>
9cd^-1      3
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3
Dimas [21]

Answer:

5-i

Step-by-step explanation:

Product=multiplication

Let the complex number=x

(3+2i)*x=17+7i

x=17+7i / 3+2i

x=(17-7i)*(3-2i)/(3+2i)*(3+2i)

=51-34i+21i+14i^2 / 9+6i+6i+4i^2

=51+13i+14i^2 / 9+12i+4i^2

= (51+14 - 13i) / 13

= (65 -13i) / 13

= 65 / 13 - 13 i / 13

= 5 - i.

5 0
3 years ago
Solve for v. -8 +5v=-33​
Dima020 [189]

Answer:

v = -5

Step-by-step explanation:

Step 1: Write out equation

-8 + 5v = -33

Step 2: Add 8 on both sides

-8 + 8 + 5v = -33 + 8

5v = -25

Step 3: Divide both sides by 5

5v/5 = -25/5

v = -5

3 0
3 years ago
Read 2 more answers
Use a normal approximation to find the probability of the indicated number of voters. In this case, assume that 104 eligible vot
crimeas [40]

Answer:

The probability that exactly 27 of 104 eligible voters voted is​ 0.057 = 5.7%.

Step-by-step explanation:

Binomial probability distribution

Probability of exactly x sucesses on n repeated trials, with p probability.

Can be approximated to a normal distribution, using the expected value and the standard deviation.

The expected value of the binomial distribution is:

E(X) = np

The standard deviation of the binomial distribution is:

\sqrt{V(X)} = \sqrt{np(1-p)}

Normal probability distribution

Problems of normally distributed distributions can be solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

When we are approximating a binomial distribution to a normal one, we have that \mu = E(X), \sigma = \sqrt{V(X)}.

In this case, assume that 104 eligible voters aged 18-24 are randomly selected.

This means that n = 104.

Suppose a previous study showed that among eligible voters aged 18-24, 22% of them voted.

This means that p = 0.22

Mean and standard deviation:

\mu = 104*0.22 = 22.88

\sigma = \sqrt{104*0.22*0.78} = 4.2245

Probability that exactly 27 voted

By continuity continuity, 27 consists of values between 26.5 and 27.5, which means that this probability is the p-value of Z when X = 27.5 subtracted by the p-value of Z when X = 26.5.

X = 27.5

Z = \frac{X - \mu}{\sigma}

Z = \frac{27.5 - 22.88}{4.2245}

Z = 1.09

Z = 1.09 has a p-value of 0.8621

X = 26.5

Z = \frac{X - \mu}{\sigma}

Z = \frac{26.5 - 22.88}{4.2245}

Z = 0.86

Z = 0.86 has a p-value of 0.8051

0.8621 - 0.8051 = 0.057

The probability that exactly 27 of 104 eligible voters voted is​ 0.057 = 5.7%.

5 0
3 years ago
Can somebody help a girl out ‍♀️
oee [108]

Answer: The second option

7 0
3 years ago
Use Newton's method to approximate the zero of the function f(x)=x^3-4x+33 to five decimal places. Round any intermediate calcul
Sidana [21]
The answer for this is f(c) x^3-4x+33
7 0
1 year ago
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