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iogann1982 [59]
3 years ago
8

How do you solve...3c^3d/9cd^-1

Mathematics
1 answer:
Maksim231197 [3]3 years ago
4 0
<u>  3c³d  </u>  = <u>c²d²</u>
9cd^-1      3
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Solve for x.<br> Explain each step you took to solve this question.<br> 30<br> (9x-3)
lapo4ka [179]
I believe the answer would be X=7
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3 0
3 years ago
Caitlyn’s family has a circular swimming pool. The circumference of the pool is 25.12m What is its area?
Natasha2012 [34]

Answer:

A = 50.26 sq meters

Step-by-step explanation:

we have to find the diameter first by using the circumference:

C = πd

25.12 = πd

25.12/π = d

8 = d

this means the radius is 4

A = πr²

A = π4² or 16π

A = 50.26 sq meters

4 0
3 years ago
What is the slope of the line that passes through the points (-7, -7) and (-7, 1) ?
ICE Princess25 [194]

Answer:

undefined

Step-by-step explanation:

(-7, -7) and (-7, 1)

To find the slope of the line, we use the slope formula: (y₂ - y₁) / (x₂ - x₁)

Plug in these values:

(1 - (-7)) / (-7 - (-7))

Simplify the parentheses.

= (1 + 7) / (-7 + 7)

Simplify the fraction.

8/0

= undefined

Our line is a vertical line, which has an undefined slope.

Hope this helps!

6 0
3 years ago
(2b + 3r) + (4b+ r)
Pavlova-9 [17]
Let's simplify step-by-step. 
<span><span><span><span>2b</span>+<span>3r</span></span>+<span>4b</span></span>+r</span>

Combine Like Terms: 
<span>=<span><span><span><span>2b</span>+<span>3r</span></span>+<span>4b</span></span>+r
</span></span><span>=<span><span>(<span><span>2b</span>+<span>4b</span></span>)</span>+<span>(<span><span>3r</span>+r</span>)
</span></span></span><span>=<span><span>6b</span>+<span>4r</span></span></span>

Answer:<span>=<span><span>6b</span>+<span>4<span>r</span></span></span></span>
4 0
3 years ago
a group of astronauts launched a model rocket from a platform. Its flight path is modeled by h= -4t^2+24t+13 where h is the heig
Eddi Din [679]

Answer:

6.5 seconds

Step-by-step explanation:

Keep in mind that when h=0, this is the same height for both when the model rocket takes off and lands, so when the rocket lands, time is positive. Thus:

h=-4t^2+24t+13\\\\0=-4t^2+24t+13\\\\t=\frac{-b\pm\sqrt{b^2-4ac}}{2a}\\ \\t=\frac{-24\pm\sqrt{24^2-4(-4)(13)}}{2(-4)}\\ \\t=\frac{-24\pm\sqrt{576+208}}{-8}\\\\t=\frac{-24\pm\sqrt{576+208}}{-8}\\\\t=\frac{-24\pm\sqrt{784}}{-8}\\\\t=\frac{-24\pm28}{-8}\\\\t=\frac{-24-28}{-8}\\ \\t=\frac{-52}{-8}\\ \\t=\frac{52}{8}\\\\t=6.5

So, the amount of seconds that the model rocket stayed above the ground since it left the platform is 6.5 seconds

5 0
2 years ago
Read 2 more answers
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