3 years ago

How do you solve...3c^3d/9cd^-1

Mathematics

1 answer:

Maksim231197 [3]3 years ago

4 0

3c³d = c²d²
9cd^-1 3

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Use the Venn diagram to calculate probabilities

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From the Venn diagram, we can gather that there are 35 total objects (6 in both A and B; 15 in A but not B; 10 in B but not A; and 4 in neither A nor B), and we have the probabilities

$\mathbb P(A\cap B)=\dfrac6{35}$

$\mathbb P(A)=\dfrac{15+6}{35}=\dfrac{21}{35}=\dfrac35$ (this is the answer)

$\mathbb P(B)=\dfrac{10+6}{35}=\dfrac{16}{35}$

By definition of conditional probability,

$P(A\mid B)=\dfrac{P(A\cap B)}{P(B)}=\dfrac{\frac6{35}}{\frac{16}{35}}=\dfrac6{16}=\dfrac38$

$P(B\mid A)=\dfrac{P(B\cap A)}{P(A)}=\dfrac{\frac6{35}}{\frac{21}{35}}=\dfrac6{21}=\dfrac27$

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