See attachment for the drawing of the perpendicular at a point c on line ab such the ac = 3.5 cm
<h3>How to draw the perpendicular at a point c on line ab such the ac = 3.5 cm?</h3>
The given parameters are:
Length of segment AB = 7 cm
Also, we have:
Point C is located on line segment AB
This means that:
Length of segment AC = Length of segment BC = 3.5 cm
When represented on a line segment, we have:
A C B
See attachment for the drawing of the perpendicular at a point c on line ab such the ac = 3.5 cm
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Angle A = 3x - 10
Angle B = x
Their angle sum = 90° ( complementary angles form 90° )
This can be written in an equation as =
= 3x - 10 + x = 90
= 3x + × + ( -10 ) = 90
= 4x + (-10) = 90
= 4x = 90 + 10 ( transposing-10 from LHS to RHS changes-10 to +10 )
= 4x = 100
= x = 100 ÷ 4 ( transposing ×4 from LHS to RHS changes ×4 to ÷4 )
= x = 25
Angle A = 3x - 10
= 3 × 25 - 10
= 75 - 10
= Angle A = 65°
Angle B = x = 25°
Their sum = 65 + 25 = 90°
Therefore , the complementary angles , Angle A = 65° and Angle B = 25° .
Factor the expression.
3(128j+3)
Yeah, x= 7/2 and y= -5/2
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Step-by-step explanation:
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