0 planes contain points J, K, and N.
Given that, planes X and Y and points J, K, L, M and N.
We need to find exactly how many planes contain points J, K, and N.
From the figure, we can see Point J doesn't belong to the planes X and Y and Point K and N belong to the plane X.
Since, points J, K, and N together do not belongs to any single plane, the planes contain points J, K, and N is 0.
Therefore, 0 planes contain points J, K, and N.
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Answer:
Explanation:
The expression that you want to simplify is:
This is the simplification step-by-step:
1. Mulitply the expressions on the numerator among them and the expressions on the denominator among them:
2. For equal bases that are multiplying, add the exponents:
3. Pass the power on the denominator to the numerator by changing its sign (negative exponents become positive when inverted)
4. Simplify adding the exponents with the same base:
And that is the final expression in its most simple form.
Answer:
i believe your answer is.
4,789,658,950
Step-by-step explanation:
Answer:
Step-by-step explanation:
65÷b+8×4=20
Put the value of b=5 in equation
65÷5+8×4=20
According to BDMAS rule
13+32=20
45=20
Bring the terms on one side
45-20=25 Answer
5 single shots and 45 double shots
Hope this helps! May I have brainliest please? :D