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Keith_Richards [23]
4 years ago
14

Solve for an angle in right triangles

Mathematics
1 answer:
madreJ [45]4 years ago
5 0

The angle of B is 56.2 degrees

<em><u>Solution:</u></em>

Given is a right angled triangle ABC

From given figure,

AB = 9

CB = 5

We have to find the angle of B

Let the angle of B be \theta

By definition of cosine,

cos \theta = \frac{adjacent}{hypotenuse}

Here, adjacent = CB and hypotenuse = AB

Therefore,

cos \theta = \frac{5}{9}\\\\cos \theta = 0.556

Taking cos inverse on both sides,

\theta = cos^{-1}(0.556)\\\\\theta = 56.22038005 \approx 56.22

Thus the angle of B is 56.22 degrees

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Thus these lines are SKEWED LINES

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