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2 years ago

Multiplying Integers with Integer Tiles –5(–2) =

Mathematics

2 answers:

Taya2010 [7]2 years ago

3 0

Answer:

-5 x -2 = 10

Step-by-step explanation:

- x - = +

5 x 2 = 10

butalik [34]2 years ago

3 0

The answer is 10 because a negative number times a negative number is a positive number

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Simplify completely 12x^3-4x^2+8x/-2x PLEASE HELP

Amiraneli [1.4K]

The answer is 12x^3-4×^2-4

4 0

2 years ago

When the function ƒ(x) = 4x−2 is evaluated for x = 3, the output is: -4 -6 -16 -none

Mkey [24]

Answer:

None

General Formulas and Concepts:

Pre-Algebra

Order of Operations: BPEMDAS

Brackets
Parenthesis
Exponents
Multiplication
Division
Addition
Subtraction

Left to Right

Algebra I

Terms/Coefficients

Step-by-step explanation:

Step 1: Define

f(x) = 4x - 2

x = 3

Step 2: Evaluate

Substitute in x [Function]: f(3) = 4(3) - 2
Multiply: f(3) = 12 - 2
Subtract: f(3) = 10

7 0

2 years ago

In XYZ, mX=90 and mY=30.In TUV,mU= 30 and mV=60. Which is true about the two triangles? XYZ=TUV, XYZ= VUT,No congruency statemen

Flauer [41]

Answer:

No congruency statement can be made because the side length are unknown.

Step-by-step explanation:

The sum of the measures of all interior angles in a triangle is always 180°.

In triangle XYZ,

$m\angle X=90^{\circ}\\ \\m\angle Y=30^{\circ},$

then

$m\angle X+m\angle Y+m\angle Z=180^{\circ}\Rightarrow m\angle Z=180^{\circ}-90^{\circ}-30^{\circ}=60^{\circ}$

In triangle TUV,

$m\angle U=30^{\circ}\\\\m\angle V=60^{\circ},$

then

$m\angle T+m\angle U+m\angle V=180^{\circ}\Rightarrow m\angle T=180^{\circ}-30^{\circ}-60^{\circ}=90^{\circ}$

We have two triangles with congruent angles but we have no information about side lengths. Therefore, can not be made because the side length are unknown. Correct option is last option.

6 0

3 years ago

Read 2 more answers

Vanessa uses the expressions (3x² + 5x + 10) and (x² – 3x - 1) to represent the length and width of her patio.

Kay [80]

Answer:

a) 3x⁴-4x³-8x²-35x-10

Step-by-step explanation:

3x2(x²-3x-1)+5x(x²-3x-1)+10(x²-3x-1)

3x⁴-9x³-3x²+5x³-15x²-5x+10x²-30x-10

3x⁴-9x³+5x³-3x²-15x²+10x²-5x-30x-10

3x⁴-4x³-8x²-35x-10

5 0

2 years ago

I walk each day to school. By what percentage would I need to increase my usual average speed in order for the journey to take 2

lesya692 [45]

Answer:

25%

Step-by-step explanation:

Let v, t be the current average speed and the time taken to reach the school respectively.

As distance = speed x time, so,

distance, d=vt...(i)

Let V be the new average speed in order to to take 20% less time than t.

So, time taken with speed V = t-20% of t = t- 0.2t= 0.8t

As distance is constant, so

d= V(0.8t)= 0.8Vt

hBy using equation (i), we have

0.8Vt = vt

0.8 V = v

V= v/0.8=1.25v

Therefore, the percentage increase in the average speed = $\frac{V-v}{v}\times 100$

$=\frac{1.25v-v}{v}\times 100$

=25%

Hence, the percentage increase in the average speed is 25%.

8 0

2 years ago