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Sliva [168]
2 years ago
8

Multiplying Integers with Integer Tiles –5(–2) =

Mathematics
2 answers:
Taya2010 [7]2 years ago
3 0

Answer:

-5 x -2 = 10

Step-by-step explanation:

- x - = +

5 x 2 = 10

butalik [34]2 years ago
3 0
The answer is 10 because a negative number times a negative number is a positive number
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Evaluate 5(x + y)2 when x = 3 and y = 9
irakobra [83]

Hey there!

Answer:\boxed{120}

Explanation:

5(x+y)2 when x = 3 and y = 9

Let's first move to x and y.

x=3\\y=9\\3+9=12

Now multiply 5 by x and y(3+9).

5*12(\text{x and y combined)}=60

Now we have the number 2 left, so we have to multiply 60 by 2.

60*2=120

\boxed{120}\text{ is your final answer.}

Hope this helps!

\text{-TestedHyperr}

4 0
3 years ago
Find the magnitude and direction in degrees of the vector v=6i+2 seq31​
masha68 [24]

Answer:

Please check the explanation.

Step-by-step explanation:

Given the vector

v = 6i + 2√3j

The Magnitude of a vector:

\mathrm{Computing\:the\:Euclidean\:Length\:of\:a\:vector}:\quad \left|\left(x_1\:,\:\:\ldots \:,\:\:x_n\right)\right|=\sqrt{\sum _{i=1}^n\left|x_i\right|^2}

=\sqrt{6^2+\left(2\sqrt{3}\right)^2}

=\sqrt{36+12}

=\sqrt{48}

\mathrm{Apply\:radical\:rule}:\quad \sqrt[n]{ab}=\sqrt[n]{a}\sqrt[n]{b}

=\sqrt{3}\sqrt{2^4}

=4\sqrt{3}

The Direction of a vector:

tan Ф = y/x

y=2√3

x = 6

tan Ф = y/x

          = 2√3 / 6

           = √3 / 3                  

\theta \:=tan\:^{-1}\left(\frac{\sqrt{3}}{3}\right)

\:\theta \:=\frac{\pi \:}{6}=30^{\circ \:}

6 0
2 years ago
I need help! I would appreciate if you show me the work! Thank you !
iVinArrow [24]

Answer:

-11 for the first one and 0 for the second one

Step-by-step explanation:

4 0
2 years ago
Read 2 more answers
What value of c makes x2 − 12x + c a perfect square trinomial? −36 −24 24 36
rewona [7]
Take half of the middle coefficient.
Then square it.

-12/2 = -6

(-6)^2 = 36

c = 36
8 0
3 years ago
Read 2 more answers
What is the area of the pentagon shown? 16 cm 15 cm 18 cm 20 cm 360 cm2 354 cm2 300 cm2 297 cm2​
nexus9112 [7]
U need upload the image
6 0
2 years ago
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